Poisson
Poisson

Reputation: 1623

compute mean of a column with python

I have a dataframe df :

TIMESTAMP equipement1 equipement2
2016-05-10 13:20:00 0.000000 0.000000
2016-05-10 14:40:00 0.400000 0.500000
2016-05-10 15:20:00 0.500000 0.500000

I would like to compute for each equipmeentx the ratio when timestamp in [TS_min, TS_max] For example function :

def ratio(df, 2016-05-10 14:40:00, 2016-05-10 15:20:00)
TIMESTAMP equipement1 equipement2
2016-05-10 14:40:00 0.4/(0.4+0.5) 0.5/(0.5+0.5)
2016-05-10 15:20:00 0.5/(0.4+0.5) 0.5/(0.5+0.5)

Any idea to help me please?

Thank you

Upvotes: 0

Views: 129

Answers (1)

Zeugma
Zeugma

Reputation: 32095

Assuming TIMESTAMP is a datetime type, here is one way:

df = df.set_index('TIMESTAMP')
r = df.ix['2016-05-10 14:40:00':'2016-05-10 15:20:00']
r/r.sum()

                     equipement1  equipement2
TIMESTAMP
2016-05-10 14:40:00     0.444444          0.5
2016-05-10 15:20:00     0.555556          0.5

Upvotes: 1

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