CODEWITHSUNDEEP
ctimeval
dasen
dasen

Reputation: 1

How do I separately convert a struct timeval into two 32 bit variables?

A struct timeval is 64 bit long. I need, for a project, to convert this long (struct timeval) into two 32 bit chunks, and put each chunk into a different variable. How do I do this? Thanx in advance.

Upvotes: 0

Views: 1868

Answers (4)

Jonathan
Jonathan

Reputation: 13624

struct timeval tv;
...
uint32_t seconds = tv.tv_sec;
uint32_t micros = tv.tv_usec;

There you go, separated into 32-bit integers.

Upvotes: 0

BЈовић
BЈовић

Reputation: 64223

See this : http://linux.die.net/man/2/gettimeofday

Can you use tv_sec and tv_usec fields of the timeval structure?

Upvotes: 0

nothrow
nothrow

Reputation: 16168

As an addition to leppie's answer:

union tvs
{
    struct timeval tv;
    struct ints {
        uint32_t v1;
        uint32_t v2;
    };
};

tvs t;
t.tv = timevalstruct;
uint32_t v1 = tv.ints.v1;
uint32_t v2 = tv.ints.v2;

if you dont want to deal with pointers.

Upvotes: 1

leppie
leppie

Reputation: 117260

uint32_t* values = &timevalstruct;

// depends on endianess

uint32_t v1 = values[0];
uint32_t v2 = values[1];

Upvotes: 2

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