CODEWITHSUNDEEP
javascriptjavascript-inheritance
Geeky
Geeky

Reputation: 7488

Confusion With Javascript Inheritance

I'm confused about javascript inheritance.

Consider the following code:

function parent(firstname, lastname) {
    this.firstname = firstname || "abc";
    this.lastname = lastname || "def";
}

function child() {
   this.childname = "xys";
}
parent.prototype.Greetings = function () {
    alert("sayhi");
}
child.prototype = Object.create(parent.prototype);
var child1 = new child();

Now, does the child1 object have access to the firstname and lastname properties? I can access the Greetings method (because it's in the prototype). If I try to access these, it is showing as undefined. What changes have to be made to access these variables?

Upvotes: 0

Views: 241

Answers (2)

Andrew Moore
Andrew Moore

Reputation: 159

A better way to do this is using more recent ES2015 standards. The syntax is much clearer to follow. Do something like:

class Parent {
    constructor(firstname, lastname) {
        this.firstname = firstname || "abc";
        this.lastname = lastname || "def";
    }
    greetings() {
        alert("sayhi");
    }
}

class Child extends Parent {
    constructor(){
        super(firstname, lastname);
        this.childname = "xys";
    }
}
var child1 = new child();

Info on ES2015 can be found at https://babeljs.io/docs/learn-es2015/ . Also, more specifics on class declarations in javascript can be found here: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Classes .

Upvotes: 0

Felix Kling
Felix Kling

Reputation: 816272

What changes has to be done to access these variables?

You have to call the parent constructor in the child constructor:

function child() {
  parent.call(this);
  this.childname = "xys";
}

JavaScript "inheritance" is a lot less magical (i.e. implicit) than in other languages (before ES6 classes at least).

In your example you have a function parent which sets two properties on this. However, nowhere in your code are you calling parent, so these properties will never be set.

In order to set them we need to apply parent to the new child instance, which is done by calling parent.call(this);.

Since parent accepts arguments, you probably want to pass them through child eventually:

function child(firstname, lastname) {
  parent.call(this, firstname, lastname);
  this.childname = "xys";
}

Related: Benefits of using `Object.create` for inheritance

Upvotes: 1

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