CODEWITHSUNDEEP
androiddatabaseback4app
user3501779
user3501779

Reputation: 169

Get notification when a user wants to add data to the database

I'm about to begin working on a recipe Android app for my college final project, and I want users to be able to add recipes to the database. However, I don't want the data to be added right away, but I'd like to receive a notification whenever someone wants to add a recipe, so I can confirm it myself. I'm using back{4}app by the way.

How can I do such a thing in a not-so-complicated way? I was thinking to create an admin account for myself in the app itself, but is there any way to send the notifications to said account? I also want to be able to confirm recipe addition with a simple "Confirm" button from within the app, so will this require me to create an additional class for pending recipes? Will I need an admin account in any case?

Upvotes: 2

Views: 615

Answers (1)

os-lopez-ne
os-lopez-ne

Reputation: 56

all this can be achieve by using cloud code. 

Parse.cloud.define("addRecipe", function(request, response) {
    const query = new Parse.Query("recipe");
    query.set("name", "name");
    query.save({
         success function(result) {
              response(result);
              //call push notification function from client or from cloud code when the error is nil 
         },
         error: function(result, error) {
          response(error);
          }
    });
});

this is an example of push notifications using cloud code. push notification are not allow anymore from the client due to secure reason. you should be subscribe to this channel

Parse.Cloud.define("pushsample", function (request, response) {
    Parse.Push.send({
        channels: ["channelName"],
        data: {
            title: "Hello!",
            message: "Hello from the Cloud Code",
        }
   }, {
        success: function () {
            // Push was successful
            response.sucess("push sent");
        },
        error: function (error) {
        // Push was unsucessful
        response.sucess("error with push: " + error);
        },
        useMasterKey: true
   });
});

you should also implement some logic to your app in order to display recipes confirm by admin. 

var recipe = Parse.Object.extend("recipe");
var query = new Parse.Query(recipe);
query.equalTo("confirm", true);
query.find({
  success: function(results) {
    //it will display recipes confirmed
  },
  error: function(error) {
    alert("Error: " + error.code + " " + error.message);
  });

you should also setup a admin system in your app or a website

Upvotes: 1

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