Reputation: 6896
On my website (MVC and web API) I have added a preloader for a better user experience purpose.
I have added the preloader at two points:
I did it with an image that I show
when the page/data loads and I hide
when the data is fully loaded.
<div id="dvReqSpinner" style="display: none;">
<br />
<center><img src="~/images/loading_spinner.gif" /></center>
<br />
</div>
And with jquery I show
and hide
it:
$("#dvReqSpinner").show();
$("#dvReqSpinner").hide();
It's a little bit anoying to keep showing and hiding an image every time I need to load data (using an AJAX call to web API, authenticating the user etc.. - Every action that takes time and I want to show the user that something is "happening"), isn't there any "automatic" option to have a preloader on a website?
Upvotes: 0
Views: 1057
Reputation: 470
I don't know if its the case, but if you use jquery ajax to handle your requests, you can do something like this:
$(document).ajaxStart(function() {
// every time a request starts
$("#dvReqSpinner").show();
}).ajaxStop(function() {
// every time a request ends
$("#dvReqSpinner").hide();
});
EDIT: If you want to avoid showing the spinner for fast requests, i think this can make it work:
var delayms = 3000; // 3 seconds
var spinnerTimeOut = null;
$(document).ajaxStart(function() {
// for every request, wait for {delayms}, then show spinner
if(spinnerTimeOut!=null){
clearTimeout(spinnerTimeOut);
}
spinnerTimeOut = setTimeout(function(){
$("#dvReqSpinner").show();
}, delayms);
}).ajaxStop(function() {
// every time a request ends
clearTimeout(spinnerTimeOut); // cancel timeout execution
$("#dvReqSpinner").hide();
});
Give it a try. i couldn't test it -.-'
Upvotes: 2
Reputation: 3878
You can use global ajax handlers for this.
This code will execute whenever you make an ajax request. all you have to do here is enable your spinner.
$( document ).ajaxSend(function() {
$("#dvReqSpinner").show();
});
This code will execute once your ajax request succeeded. all you have to do here is enable your spinner.
$( document ).ajaxSuccess(function( event, request, settings ) {
$("#dvReqSpinner").hide();
});
You can also use other global ajax function to handle things like showing a popup when a ajax request fails using ".ajaxError()"
Below link will have details of all the other functions
https://api.jquery.com/category/ajax/global-ajax-event-handlers/
Upvotes: 0
Reputation: 338228
To show or hide a loading indicator in a single page app, I would add and remove a CSS class from the body:
#dvReqSpinner {
display: none;
}
body.loading #dvReqSpinner {
display: block;
}
and
$("body").addClass("loading");
$("body").removeClass("loading");
Primarily this would make the JS code independent on the actual page layout, so it's "nicer" but not really "less work".
To do it "automatically", I recommend abstracting your Ajax layer into a helper object:
var API = {
runningCalls: 0,
// basic function that is responsible for all Ajax calls and housekeeping
ajax: function (options) {
var self = this;
self.runningCalls++;
$("body").addClass("loading");
return $.ajax(options).always(function () {
self.runningCalls--;
if (self.runningCalls === 0) $("body").removeClass("loading");
}).fail(function (jqXhr, status, error) {
console.log(error);
});
},
// generic GET to be used by more specialized functions
get: function (url, params) {
return this.ajax({
method: 'GET',
url: url,
data: params
});
},
// generic POST to be used by more specialized functions
post: function (url, params) {
return this.ajax({
method: 'POST',
url: url,
data: params
});
},
// generic POST JSON to be used by more specialized functions
postJson: function (url, params) {
return this.ajax({
method: 'POST',
url: url,
data: JSON.stringify(params),
dataType: 'json'
});
},
// specialized function to return That Thing with a certain ID
getThatThing: function (id) {
return this.get("/api/thatThing", {id: id});
}
// and so on ...
};
so that later, in your application code, you can call it very simply like this:
API.getThatThing(5).done(function (result) {
// show result on your page
});
and be sure that the low-level stuff like showing the spinner has been taken care of.
Upvotes: 2