Reputation: 440
I am trying to use this code to send my application apk file to another device:
public static void sendAppItself(Activity paramActivity) throws IOException {
PackageManager pm = paramActivity.getPackageManager();
ApplicationInfo appInfo;
try {
appInfo = pm.getApplicationInfo(paramActivity.getPackageName(),
PackageManager.GET_META_DATA);
Intent sendBt = new Intent(Intent.ACTION_SEND);
sendBt.setType("*/*");
sendBt.putExtra(Intent.EXTRA_STREAM,
Uri.parse("file://" + appInfo.publicSourceDir));
paramActivity.startActivity(Intent.createChooser(sendBt,
"Share it using"));
} catch (PackageManager.NameNotFoundException e1) {
e1.printStackTrace();
}
}
This code works very well.
But the name of the apk file shared with this code is base.apk
How can I change it?
Upvotes: 7
Views: 9619
Reputation: 1976
First we need to set a file provider In AndroidManifest.xml create a File provider
<provider
android:name="androidx.core.content.FileProvider"
android:authorities="${applicationId}.provider"
android:exported="false"
android:grantUriPermissions="true"
>
<meta-data
android:name="android.support.FILE_PROVIDER_PATHS"
android:resource="@xml/file_paths"
/>
</provider>
If you don't have file_path.xml the create one in res/xml (create xml folder if it doesn't exist) and in file_path.xml add
<?xml version="1.0" encoding="utf-8"?>
<paths>
<external-files-path
name="apk"
path="cache/ExtractedApk/" />
</paths>
Now add the code to share the apk
private fun shareAppAsAPK(context: Context) {
val app: ApplicationInfo = context.applicationInfo
val originalApk = app.publicSourceDir
try {
//Make new directory in new location
var tempFile: File = File(App.instance.getExternalCacheDir().toString() + "/ExtractedApk")
//If directory doesn't exists create new
if (!tempFile.isDirectory) if (!tempFile.mkdirs()) return
//rename apk file to app name
tempFile = File(tempFile.path + "/" + getString(app.labelRes).replace(" ", "") + ".apk")
//If file doesn't exists create new
if (!tempFile.exists()) {
if (!tempFile.createNewFile()) {
return
}
}
//Copy file to new location
val inp: InputStream = FileInputStream(originalApk)
val out: OutputStream = FileOutputStream(tempFile)
val buf = ByteArray(1024)
var len: Int
while (inp.read(buf).also { len = it } > 0) {
out.write(buf, 0, len)
}
inp.close()
out.close()
//Open share dialog
val intent = Intent(Intent.ACTION_SEND)
//MIME type for apk, might not work in bluetooth sahre as it doesn't support apk MIME type
intent.type = "application/vnd.android.package-archive"
intent.putExtra(
Intent.EXTRA_STREAM, FileProvider.getUriForFile(
context, BuildConfig.APPLICATION_ID + ".fileprovider", File(tempFile.path)
)
)
intent.addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION)
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK)
intent.addFlags(Intent.FLAG_ACTIVITY_SINGLE_TOP)
startActivity(intent)
} catch (e: IOException) {
e.printStackTrace()
}
}
Upvotes: 1
Reputation: 497
If someone trying to generate apk from fragment they may need to change few lines from @sajad's answer as below
Replace
File tempFile = new File(getExternalCacheDir() + "/ExtractedApk");
with
File tempFile = new File(getActivity().getExternalCacheDir() + "/ExtractedApk");
2.while importing BuildConfig for below line
import androidx.multidex.BuildConfig
// DO NOT DO THIS!!! , use your app BuildConfig.
and if you're getting below EXCEPTION
Couldn't find meta-data for provider with authority
then look for "provider"s name and authority in your manifest file and if it's androidx.core.content.FileProvider
then
Replace
Uri photoURI = FileProvider.getUriForFile(this, BuildConfig.APPLICATION_ID + ".provider", tempFile);
With
Uri photoURI = FileProvider.getUriForFile(getActivity(), BuildConfig.APPLICATION_ID + ".fileprovider", tempFile);
Upvotes: 0
Reputation: 474
Copy the file from the source directory to a new directory. Rename the file while copying and share the copied file. Delete the temp file after share is complete.
private void shareApplication() {
ApplicationInfo app = getApplicationContext().getApplicationInfo();
String filePath = app.sourceDir;
Intent intent = new Intent(Intent.ACTION_SEND);
// MIME of .apk is "application/vnd.android.package-archive".
// but Bluetooth does not accept this. Let's use "*/*" instead.
intent.setType("*/*");
// Append file and send Intent
File originalApk = new File(filePath);
try {
//Make new directory in new location
File tempFile = new File(getExternalCacheDir() + "/ExtractedApk");
//If directory doesn't exists create new
if (!tempFile.isDirectory())
if (!tempFile.mkdirs())
return;
//Get application's name and convert to lowercase
tempFile = new File(tempFile.getPath() + "/" + getString(app.labelRes).replace(" ","").toLowerCase() + ".apk");
//If file doesn't exists create new
if (!tempFile.exists()) {
if (!tempFile.createNewFile()) {
return;
}
}
//Copy file to new location
InputStream in = new FileInputStream(originalApk);
OutputStream out = new FileOutputStream(tempFile);
byte[] buf = new byte[1024];
int len;
while ((len = in.read(buf)) > 0) {
out.write(buf, 0, len);
}
in.close();
out.close();
System.out.println("File copied.");
//Open share dialog
intent.putExtra(Intent.EXTRA_STREAM, Uri.fromFile(tempFile));
startActivity(Intent.createChooser(intent, "Share app via"));
} catch (IOException e) {
e.printStackTrace();
}
}
Update: this method does not work anymore and throws exception if you implement it. Since android N, we should use content providers if we want to have access to files in memory(like the apk file). For more information please visit this Guide. Although the whole idea of copying and renaming and sharing the copied version is still valid.
Upvotes: 17
Reputation: 2184
You can use this function, test on api 22 and 27
private void shareApplication() {
ApplicationInfo app = getApplicationContext().getApplicationInfo();
String filePath = app.sourceDir;
Intent intent = new Intent(Intent.ACTION_SEND);
// MIME of .apk is "application/vnd.android.package-archive".
// but Bluetooth does not accept this. Let's use "*/*" instead.
intent.setType("*/*");
// Append file and send Intent
File originalApk = new File(filePath);
try {
//Make new directory in new location=
File tempFile = new File(getExternalCacheDir() + "/ExtractedApk");
//If directory doesn't exists create new
if (!tempFile.isDirectory())
if (!tempFile.mkdirs())
return;
//Get application's name and convert to lowercase
tempFile = new File(tempFile.getPath() + "/" + getString(app.labelRes).replace(" ","").toLowerCase() + ".apk");
//If file doesn't exists create new
if (!tempFile.exists()) {
if (!tempFile.createNewFile()) {
return;
}
}
//Copy file to new location
InputStream in = new FileInputStream(originalApk);
OutputStream out = new FileOutputStream(tempFile);
byte[] buf = new byte[1024];
int len;
while ((len = in.read(buf)) > 0) {
out.write(buf, 0, len);
}
in.close();
out.close();
System.out.println("File copied.");
//Open share dialog
// intent.putExtra(Intent.EXTRA_STREAM, Uri.fromFile(tempFile));
Uri photoURI = FileProvider.getUriForFile(this, BuildConfig.APPLICATION_ID + ".provider", tempFile);
// intent.putExtra(Intent.EXTRA_STREAM, Uri.fromFile(tempFile));
intent.putExtra(Intent.EXTRA_STREAM, photoURI);
startActivity(Intent.createChooser(intent, "Share app via"));
} catch (IOException e) {
e.printStackTrace();
}
}
Upvotes: 3
Reputation: 3632
This only happens because it is saved by base.apk name. To share it as per your need you have to just copy this file into another directory path and rename it over there. Then use new file to share.
This file path[file:///data/app/com.yourapppackagename/base.apk] in data folder is having only read permissions so you can't rename .apk file over there.
Upvotes: 2