CODEWITHSUNDEEP
regexgo
Colleen Larsen
Colleen Larsen

Reputation: 733

How to get everything within brackets in golang with regex

I am trying to get everything within the outside brackets of the following sql statement in golang regular expressions.

Categories
(// = outside bracket
PersonID int,
LastName varchar(255),
FirstName varchar(255),
Address varchar(255),
City varchar(255)
)//=outside bracket

how would I use regex to only identify the outer brackets and return everything in between the outside brackets?

Upvotes: 3

Views: 6271

Answers (1)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626747

All you need is to find the first (, then match any characters up to the last ) with

`(?s)\((.*)\)`

Details:

  • (?s) - allow . to match any character, including a newline
  • \( - a literal ( char
  • (.*) - Submatch 1 capturing any zero or more characters
  • \) - a literal ) symbol.

See the Go demo:

package main

import (
    "fmt"
    "regexp"
)

func main() {
    s := `Categories
(// = outside bracket
PersonID int,
LastName varchar(255),
FirstName varchar(255),
Address varchar(255),
City varchar(255)
)//=outside bracket`
    re := regexp.MustCompile(`(?s)\((.*)\)`)

    m := re.FindAllStringSubmatch(s,-1)
    fmt.Printf("Capture value: %s", m[0][1])
}

Upvotes: 4

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