CODEWITHSUNDEEP
pythonshellarguments
kskp
kskp

Reputation: 712

Passing arguments to Python from Shell Script

I wrote a small shell script that looks like this:

cd models/syntaxnet
var1=$(jq --raw-output '.["avl_text"]' | syntaxnet/demo.sh)
echo $var1
python /home/sree/python_code1.py $var1

My python_code1.py looks like this:

import sys

data = sys.argv[1]
print "In python code"
print data
print type(data)

Now, the output of echo $var1 in my shell script is exactly what I wanted to see:

1 Check _ VERB VB _ 0 ROOT _ _ 2 out _ PRT RP _ 1 prt _ _ 3 this _ DET DT _ 4 det _ _ 4 video _ NOUN NN _ 1 dobj _ _ 5 about _ ADP IN _ 4 prep _ _ 6 Northwest _ NOUN NNP _ 7 nn _ _ 7 Arkansas _ NOUN NNP _ 5 pobj _ _ 8 - _ . , _ 7 punct _ _ 9 https _ X ADD _ 7 appos _ _

But the output of print data in the python code is just 1. i.e. the first letter of the argument.

Why is this happening? I want to pass the entire string to the python code.

Upvotes: 16

Views: 66680

Answers (2)

Dinesh Pundkar
Dinesh Pundkar

Reputation: 4194

If there is space in between argument and argument is not in quotes, then python consider as two different arguments.

That's why the output of print data in the python code is just 1.

Check the below output.

[root@dsp-centos ~]# python dsp.py Dinesh Pundkar
In python code
Dinesh
[root@dsp-centos ~]# python dsp.py "Dinesh Pundkar"
In python code
Dinesh Pundkar
[root@dsp-centos ~]#

So, in your shell script, put $var1 in quotes.

Content of shell script(a.sh):

var1="Dinesh Pundkar"
python dsp.py "$var1"

Content of python code(dsp.py):

import sys
data = sys.argv[1]
print "In python code"
print data

Output:

[root@dsp-centos ~]# sh a.sh
In python code
Dinesh Pundkar

Upvotes: 36

somesingsomsing
somesingsomsing

Reputation: 3350

Use Join and list slicing

import sys
data = ' '.join(sys.argv[1:])
print "In python code"
print data
print type(data)

Upvotes: 5

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