CODEWITHSUNDEEP
xslt
shiming
shiming

Reputation: 13

xslt: how to select an element from a variable

For an input as below:

<Classes>
  <ClassOfService Cabin="Y" Status="6">S</ClassOfService>
  <ClassOfService Cabin="Y" Status="5">N</ClassOfService>
  <ClassOfService Cabin="Y" Status="1">Q</ClassOfService>
  <ClassOfService Cabin="Y" Status="0">O</ClassOfService>
  <ClassOfService Cabin="Y" Status="0">E</ClassOfService>
</Classes>

I want to get the first, in order of bottom to top, ClassOfService value which has stauts >=3. So it should be N. I tried following in my xsl but it doesn’t work:

  <xsl:variable name="qualifiedClass" select="Classes/ClassOfService[@Status   >=3]"/>
<xsl:variable name="numOfqClass"  select="count(Classes/ClassOfService[@Status >=3])"/> 
<xsl:value-of select="$qualifiedClass/ClassOfService[$numOfqClass]"/>

how to select an element from variable?

Alternatively, I also tried below, doesn't work either. 

<xsl:value-of select="Classes/ClassOfService[@Status>=3][last()]"/>

Upvotes: 1

Views: 49

Answers (1)

michael.hor257k
michael.hor257k

Reputation: 116959

I want to get the first, in order of bottom to top, ClassOfService value which has stauts >=3.

I think that "first, in order of bottom to top" means last, in document order (which is the order by which XPath operates).

So your attempt:

<xsl:value-of select="Classes/ClassOfService[@Status >= 3][last()]"/>

is the correct answer, and it does work if applied from the context of the / root node.

See it working here: http://xsltransform.net/3NSSEuN

Upvotes: 1

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