CODEWITHSUNDEEP
scalahexlong-integer
mCY
mCY

Reputation: 2821

Long/Int in scala to hex string

With Integer.toString(1234567, 16).toUpperCase() // output: 12D68 could help to convert an Int to Hex string.

How to do the same with Long?

Long.toString(13690566117625, 16).toUpperCase() // but this will report error

Upvotes: 15

Views: 20623

Answers (5)

Yuval Itzchakov
Yuval Itzchakov

Reputation: 149538

You're looking for RichLong.toHexString:

scala> 13690566117625L.toHexString
res0: String = c73955488f9

And the uppercase variant:

scala> 13690566117625L.toHexString.toUpperCase
res1: String = C73955488F9

Edit

This also available for Int via RichInt.toHexString:

scala> 42.toHexString
res4: String = 2a

Upvotes: 23

ForeverLearner
ForeverLearner

Reputation: 2103

The benefit of using Scala is the ability to use Java libraries.

So, you could implement :

import scala.util.Try
val longToHexString = Try(java.lang.Long.toString(13690566117625, 16)) // handle exceptions if any

Upvotes: 0

Martin Tapp
Martin Tapp

Reputation: 3376

I've found f"0x$int_val%08X" or f"0x$long_val%16X" to work great when you want to align a value with leading zeros.

scala> val i = 1
i: Int = 1

scala> f"0x$i%08X"
res1: String = 0x00000001

scala> val i = -1
i: Int = -1

scala> f"0x$i%08X"
res2: String = 0xFFFFFFFF

scala> val i = -1L
i: Long = -1

scala> f"0x$i%16X"
res3: String = 0xFFFFFFFFFFFFFFFF

Upvotes: 5

jwvh
jwvh

Reputation: 51271

val bigNum: Long   = 13690566117625L
val bigHex: String = f"$bigNum%X"

Use %X to get uppercase hex letters and %x if you want lowercase.

Upvotes: 15

Jesper
Jesper

Reputation: 206816

You have several errors. First of all, the number 13690566117625 is too large to fit in an int so you need to add an L prefix to indicate that it's a long literal. Second, Long does not have a toString method that takes a radix (unlike Integer).

Solution:

val x = 13690566117625L
x.toHexString.toUpperCase

Upvotes: 3

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