CODEWITHSUNDEEP
perlglob
LearningCpp
LearningCpp

Reputation: 972

glob is not picking all the files matching a pattern, is there an issue with the syntax

I have a directory where there are more than 10 files which start with pattern "my_Report". While i tried using glod for this job,it just picked only a single file . Is there any problem with the syntax below

$g_map{"Rep"} = glob ("data_1/reports/my_Report*");

Alternatively , i tried using grep to find all the files and stored it in a hash 

$g_map{"Rep"} = [grep {!/\.xh$/} <data_1/reports/my_Report*>];

My Requirement is to find all the files with specific pattern from the directory and store it in a hash with key "Rep" How do i achieve the same with glob?

Thanks in Advance

Upvotes: 2

Views: 607

Answers (2)

stevieb
stevieb

Reputation: 9296

glob returns a list, but you're calling it in scalar context, which is why you're only getting a single result. Try this:

@{ $g_map{Rep} } = glob ("data_1/reports/my_Report*");

That'll turn $g_map{Rep} hash key into an array reference, and all of the files will be stored in it.

You can access it like this:

for (@{ $g_map{Rep} }){
    print "filename: $_\n";
}

Upvotes: 2

mob
mob

Reputation: 118605

Your first call is in scalar context. In scalar context, glob returns (at most) a single result.

To retrieve all the matching files, use list context (like you do in your second call)

$g_map{"Rep"} = [ glob("data_1/reports/my_Report*") ]

or if you are expecting one result or just want the first result

($g_map{"Rep"}) = glob("data_1/reports/my_Report*");

Upvotes: 3

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