Reputation: 1587
I have a 2D intensity plot, as in this example:
[xx yy] = meshgrid(0:0.1:1, 0:0.1:1);
figure(1)
imagesc(sin(xx)) %(x,y)-plot at z=0
Now, as I have noted in the comment, this plot is in the xy
-plane and I have taken z=0
. I'd like to plot this in a 3D coordinate system as a function of x
and y
, but taking z=0
. I tried with plot3
in this way, plot3(xx,yy,cos(yy))
, but that only plots lines and gives them a curvature which I am not interested in. I'd like only a plane at z=0
.
Upvotes: 1
Views: 100
Reputation: 65460
You can use surf
to accomplish this. We use the xx
and yy
meshgrid outputs as the x
and y
positisions, a matrix of zeros
as the z
value and sin(xx)
as the color. We also remove the edges by setting the EdgeColor
to none
.
surf(xx, yy, zeros(size(xx)), sin(xx), 'EdgeColor', 'none')
Upvotes: 2