CODEWITHSUNDEEP
phpjson
i.am
i.am

Reputation: 23

google search, json_decode gives null

    $query = "Poultry meat is a major source of animal protein considering"; 

function fetch_google($query) { 
$cleanQuery = str_replace(" ","+",$query); 

$url = 'http://www.google.com/search?q='.urlencode($cleanQuery);
$data=file_get_contents($url);
$json = json_decode($data, true); 

for($x=0;$x<count($json->responseData->results);$x++){

echo "<b>Result ".($x+1)."</b>";
echo "<br>URL: ";
echo $json->responseData->results[$x]->url;
echo "<br>VisibleURL: ";
echo $json->responseData->results[$x]->visibleUrl;
echo "<br>Title: ";
echo $json->responseData->results[$x]->title;
echo "<br>Content: ";
echo $json->responseData->results[$x]->content;
echo "<br><br>";
}
  } 

  fetch_google($query);

i am try to get search result, but in return json_decode giving null values .. tried searching for answer but failed.

var_dump($url); gives result .. but not $json

Upvotes: 0

Views: 211

Answers (2)

donmath
donmath

Reputation: 1

Might also have to use this when decoding raw 'google json'

$php_json_txt = str_replace('\\x', '\\\\x', $google_json_txt);
$data = json_decode($php_json_txt, true);

Upvotes: 0

Daniel Dudas
Daniel Dudas

Reputation: 3002

You loaded the full google search results page. The result in $data will be the full HTML returned by the page, not a json formatted result.

You need to call the google API in order to receive a JSON that can be easily manipulate from PHP

Check the official documentation here about google search

Upvotes: 1

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