Reputation: 1420
I am getting an error running the code below. I believe it as to do with the number of single quotes used. How can I set a variable inside OPENQUERY command?
@declare @myStr varchar(6)
set @myStr = 'Test1'
SELECT *
FROM OPENQUERY("192.168.1.1",'SET FMTONLY OFF; EXEC spNewTest @Param1 = ''+ @myStr +''')
Click to see the error message
Regards, Elio Fernandes
Upvotes: 0
Views: 8110
Reputation: 1420
I just found the answer for my question, so I thought sharing it with you.
DECLARE @QUERY VARCHAR(MAX)
DECLARE @TSQL VARCHAR(100)
DECLARE @SP VARCHAR(50)
DECLARE @PARAMETERS VARCHAR(MAX)
DECLARE @PARAM1 VARCHAR(50)
DECLARE @PARAM2 VARCHAR(50)
SET @TSQL = N'SELECT * FROM OPENQUERY([192.168.1.1], ''SET FMTONLY OFF; '
SET @SP = 'EXEC spNewTest '
SET @PARAM1 = '@Type='''+ QUOTENAME('Test','''') + ''''
SET @PARAM2 = '@Year='''+ QUOTENAME('2016','''') + ''''
SET @PARAMETERS = @PARAM1 + ', ' + @PARAM2
SET @QUERY = @TSQL + @SP + @PARAMETERS + ''')'
EXECUTE (@QUERY)
Thanks
Upvotes: 1
Reputation: 2098
If you want to create a single quote within a string you have to put in two single quotes. For example: '''this is a string''' would be a string containing the following: 'this is a string'
So for your problem, you have to change your code to this:
@declare @myStr varchar(6)
set @myStr = 'Test1'
SELECT *
FROM OPENQUERY("192.168.1.1",'SET FMTONLY OFF; EXEC spNewTest @Param1 = '''+ @myStr +'''')
Upvotes: 1