CODEWITHSUNDEEP
c++staticanonymousunnamed-namespace
RyanC
RyanC

Reputation: 189

Accessing the variable inside anonymous namespace (c++)

I have following code and I don't know how can I access the x inside the anonymous namespace in this setting. Please tell me how?

#include <iostream>

int x = 10;

namespace
{
    int x = 20;
}

int main(int x, char* y[])
{
    {
        int x = 30; // most recently defined
        std::cout << x << std::endl; // 30, local
        std::cout << ::x << std::endl; // 10, global
        // how can I access the x inside the anonymous namespace?
    }

    return 0;
}

Upvotes: 6

Views: 3263

Answers (2)

Trevor Hickey
Trevor Hickey

Reputation: 37914

You'll have to access it from a function within the anonymous same scope: 

#include <iostream>

int x = 10;

namespace
{
    int x = 20;
    int X() { return x; }
}

int main(int x, char* y[])
{
    {
        int x = 30; // most recently defined
        std::cout << x << std::endl; // 30, local
        std::cout << ::x << std::endl; // 10, global
        std::cout << X() << std::endl; // 20, anonymous
        // how can I access the x inside the anonymous namespace?
    }

    return 0;
}

Upvotes: 0

Lightness Races in Orbit
Lightness Races in Orbit

Reputation: 385385

You can't!

You cannot access the namespace's members by its name, because it doesn't have one.
It's anonymous.

You can only access those members by virtue of their having been pulled into scope already.

Upvotes: 3

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