CODEWITHSUNDEEP
pythonapache-sparkpysparkapache-spark-sqlapache-spark-mllib
Edamame
Edamame

Reputation: 25366

AttributeError: 'DataFrame' object has no attribute 'map'

I wanted to convert the spark data frame to add using the code below:

from pyspark.mllib.clustering import KMeans
spark_df = sqlContext.createDataFrame(pandas_df)
rdd = spark_df.map(lambda data: Vectors.dense([float(c) for c in data]))
model = KMeans.train(rdd, 2, maxIterations=10, runs=30, initializationMode="random")

The detailed error message is:

---------------------------------------------------------------------------
AttributeError                            Traceback (most recent call last)
<ipython-input-11-a19a1763d3ac> in <module>()
      1 from pyspark.mllib.clustering import KMeans
      2 spark_df = sqlContext.createDataFrame(pandas_df)
----> 3 rdd = spark_df.map(lambda data: Vectors.dense([float(c) for c in data]))
      4 model = KMeans.train(rdd, 2, maxIterations=10, runs=30, initializationMode="random")

/home/edamame/spark/spark-2.0.0-bin-hadoop2.6/python/pyspark/sql/dataframe.pyc in __getattr__(self, name)
    842         if name not in self.columns:
    843             raise AttributeError(
--> 844                 "'%s' object has no attribute '%s'" % (self.__class__.__name__, name))
    845         jc = self._jdf.apply(name)
    846         return Column(jc)

AttributeError: 'DataFrame' object has no attribute 'map'

Does anyone know what I did wrong here? Thanks!

Upvotes: 53

Views: 162483

Answers (2)

Yosi Dahari
Yosi Dahari

Reputation: 6999

You can use df.rdd.map(), as DataFrame does not have map or flatMap, but be aware of the implications of using df.rdd:

Converting to RDD breaks Dataframe lineage, there is no predicate pushdown, no column prunning, no SQL plan and less efficient PySpark transformations.

What should you do instead?

Keep in mind that the high-level DataFrame API is equipped with many alternatives. First, you can use select or selectExpr.

Another example is using explode instead of flatMap(which existed in RDD):

df.select($"name",explode($"knownLanguages"))
    .show(false)

Result:

+-------+------+
|name   |col   |
+-------+------+
|James  |Java  |
|James  |Scala |
|Michael|Spark |
|Michael|Java  |
|Michael|null  |
|Robert |CSharp|
|Robert |      |
+-------+------+

You can also use withColumn or UDF, depending on the use-case, or another option in the DataFrame API.

Upvotes: 1

David
David

Reputation: 11573

You can't map a dataframe, but you can convert the dataframe to an RDD and map that by doing spark_df.rdd.map(). Prior to Spark 2.0, spark_df.map would alias to spark_df.rdd.map(). With Spark 2.0, you must explicitly call .rdd first.

Upvotes: 111

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