Reputation: 3148
I have a table like this:
Id Date Price Item Type
1 2009-09-21 25 1 M
2 2009-08-31 16 2 T
1 2009-09-23 21 1 M
2 2009-09-03 12 3 T
I try to receive the output of ID and column of sum price mult items for type='M' and another column with same logic for type='T'
Only way how to do it for me is using multi-cte but it is kind of complex and big:
with cte as (
select distinct a.id, a.date
sum(price*a.item) as numm
from table a
where a.type='M'
group by a.id),
crx as (
select cte.id, cte.numm, sum(a.price*a.item) as numm_1 from cte
join table a on a.id=cte.id and a.date=cte.date
where a.type='T'
group by cte.id)
select * from crx
Having a certain feeling that it can be done better (for example using subqueries)-asking you how can it be done.
p.s.
SQLlite stuff would be greatly appreciated!
Thanks!
Upvotes: 0
Views: 36
Reputation: 81960
Perhaps this will help
Declare @YourTable table (Id int,Date date,Price money,Item int,Type varchar(25))
Insert into @YourTable values
(1,'2009-09-21',25,1,'M'),
(2,'2009-08-31',16,2,'T'),
(1,'2009-09-23',21,1,'M'),
(2,'2009-09-03',12,3,'T')
Select ID
,sum(case when Type='M' then Price*Item else 0 end) as M
,sum(case when Type='T' then Price*Item else 0 end) as T
From YourTable
Group By ID
Returns
ID M T
1 46.00 0.00
2 0.00 68.00
Upvotes: 1