Reputation: 626
I have some dataset about genders of various individuals. Say, the dataset looks like this:
Male
Female
Male and Female
Male
Male
Female
Trans
Unknown
Male and Female
Some identify themselves as Male, some female and some identify themselves as both male and female.
Now, what I want to do is create a new column in Pandas which maps
Males to 1,
Females to 2,
Others to 3
I wrote some code
def gender(x):
if x.str.contains("Male")
return 1
elif x.str.contains("Female")
return 2
elif return 3
df["Gender Values"] = df["Gender"].apply(gender)
But I was getting errors that function doesn't contain any attribute contains. I tried removing str:
x.contains("Male")
and I was getting same error
Is there a better way to do this?
Upvotes: 3
Views: 10283
Reputation: 1
If there is no specific requirement to use 1, 2, 3 to Males, Females and Others respectively in that order, you can try LabelEncoder from Scikit-Learn. It will randomly allocate a unique number to each unique category in that column.
from sklearn import preprocessing
encoder = preprocessing.LabelEncoder()
encoder.fit(df["gender"])
For details, you can check Label Encoder documentation.
Hope this helps!
Upvotes: 0
Reputation: 862441
You can use:
def gender(x):
if "Female" in x and "Male" in x:
return 3
elif "Male" in x:
return 1
elif "Female" in x:
return 2
else: return 4
df["Gender Values"] = df["Gender"].apply(gender)
print (df)
Gender Gender Values
0 Male 1
1 Female 2
2 Male and Female 3
3 Male 1
4 Male 1
5 Female 2
6 Trans 4
7 Unknown 4
8 Male and Female 3
Upvotes: 11
Reputation: 8917
Create a mapping function, and use that to map the values.
def map_identity(identity):
if gender.lower() == 'male':
return 1
elif gender.lower() == 'female':
return 2
else:
return 3
df["B"] = df["A"].map(map_identity)
Upvotes: 1