CODEWITHSUNDEEP
phpdatabaseformslaravel-4
user6197965
user6197965

Reputation:

Update database of button click in laravel form

I have this on my view

{{ Form::open() }}
@if($order->paid == 0)
    <button type="submit" class="btn btn-primary" value="1">Mark Order as Paid</a>
@else
    <button type="submit" class="btn btn-primary" value="0">Mark Order as Unpaid</a>
@endif
{{ Form::close() }}

And this in my controller

public function ordersPaidSubmit($orderId) {       
    $order = Order::where('order_id', $orderId)->first();
    if (!$order) {
        App::abort(404);
}

    $paid = Input::get('paid');
    $order->save();

    return Redirect::to('/admin/orders');
}

Is it possible to give value to buttons 0 or1 like this and on click to update database column? Currently doesn't update but how can be make to update?

Upvotes: 2

Views: 2289

Answers (1)

S.I.
S.I.

Reputation: 3375

You can put one hidden field in each button like this:

{{ Form::open() }}
@if($order->paid == 0)
    {{ Form::hidden('paid', 1, ['id' => 'paid']) }}
    <button type="submit" class="btn btn-primary" value="1">Mark Order as Paid</a>
@else
    {{ Form::hidden('paid', 0, ['id' => 'paid']) }}
    <button type="submit" class="btn btn-primary" value="0">Mark Order as Unpaid</a>
@endif
{{ Form::close() }}

So hidden field will looks like

<input id="paid" name="paid" type="hidden" value="1">
and
<input id="paid" name="paid" type="hidden" value="0">

I'm sure that you want to use $order not $paid in your controller. So change this line

$paid = Input::get('paid');

whit

$order->paid = Input::get('paid');

And your form buttons will work.

Upvotes: 1

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