Reputation: 365
I am new to batch files. I have two projects and I want to run them using a batch file. projectA should run on port 8081 and projectB on 8082. I have tried the following 2 approaches, but only projectA starts on port 8081.
@echo off
SET CMB_HOME=C:\Development\CMB
cd %CMB_HOME%\projectA\
call mvn tomcat:run -Dmaven.tomcat.port=8081
cd %CMB_HOME%\projectB\
call mvn tomcat:run -Dmaven.tomcat.port=8082
Seems like the following part is not read.
cd %CMB_HOME%\projectB\
call mvn tomcat:run -Dmaven.tomcat.port=8082
I have also tried creating 2 batch files: master.bat and slave.bat.
master.bat contains the following and is calling slave.bat:
@echo off
SET CMB_HOME=C:\Development\CMB
cd %CMB_HOME%\projectA\
call mvn tomcat:run -Dmaven.tomcat.port=8081
SET SCRIPT_HOME=C:\Development\scripts\CMB
cd %SCRIPT_HOME%
call slave.bat
And slave.bat contains the following:
@echo off
SET CMB_HOME=C:\Development\CMB
cd %CMB_HOME%\projectB\
call mvn tomcat:run -Dmaven.tomcat.port=8082
Please help.
Upvotes: 0
Views: 97
Reputation: 1705
EDIT: Updated passing arguments.
@echo off
SET CMB_HOME=C:\Development\CMB
pushd %CMB_HOME%\projectA\
start "Port 8081" cmd /c "mvn tomcat:run -Dmaven.tomcat.port=8081"
popd
pushd %CMB_HOME%\projectB\
start "Port 8082" cmd /c "mvn tomcat:run -Dmaven.tomcat.port=8082"
popd
as I don't know how mvn expect its arguments you may play with the quotes in the start command
start "Port 8081" cmd/c ^""mvn "tomcat:run -Dmaven.tomcat.port=8081" ^"
...
start "Port 8082" cmd/c ^""mvn "tomcat:run -Dmaven.tomcat.port=8082" ^"
Or try a workaround...
@echo off
if "%~1" neq "" goto run
start "Port 8081" cmd /c ^""%~f0" projectA 8081 ^"
start "Port 8082" cmd /c ^""%~f0" projectB 8082 ^"
goto :eof
:run
set "PORT=%~2"
set "CMB_HOME=C:\Development\CMB\%~1\"
pushd %CMB_HOME%
call mvn tomcat:run -Dmaven.tomcat.port=%PORT%
popd
goto :eof
Upvotes: 1