CODEWITHSUNDEEP
pythonlistincrement
Velox Lupus
Velox Lupus

Reputation: 3

Creating an incremental List

When I try to create an incremental list from a to b ( so something like [1,1.1,1.2,1.3,...,2] (a=1, b=2), then I start having a problem with the specific code I came up with:

def Range(a,b,r):
    lst1=[]
    y=a
    while y<b:
        lst1.append(round(float(y+10**-r),r))
        y+=10**-r
    return lst1

print Range(1,2,3)

Here, r is the power of my increments (10**-r). For r=1 or r=2 the code works fine and ends at [...,2.0]. But for r=3 or r=4 it ends at [...,2.001] and [...,2.0001] respectively. But then, for r=5 and r=6 it goes back to ending at 2. Is there something wrong with my code or is this some sort of bug?

Upvotes: 0

Views: 667

Answers (1)

RemcoGerlich
RemcoGerlich

Reputation: 31260

say, to get a element of 2.001, the lost has to take in y=2.000

That's not true; it's possible that y becomes, say, 1.99999999999997.

You check on y < b, but then add round(float(y+10**-r),r) to the list. It's of course possible that the first is true, but the second is still larger than b.

To see what's happening, remove the rounding, and look at the next-to-last number in your lists in the cases where it's going "wrong".

Upvotes: 2

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