CODEWITHSUNDEEP
phphtmlforms
Gin.A
Gin.A

Reputation: 65

Dropdown data not being sent to $_POST php

I'm new to coding, and have encountered some difficulty with the drop-down list. Would appreciate any help given!

I have this:

<html>
    <select name="Subject">
    <option value="One">One</option>
    <option value="Two">Two</option>
    </select>
</html>

<?php
if (isset($_POST['submit'])) {
    echo $_POST['Subject']; 
}
echo '
<form method="post"><input type="submit" name="submit" value="Submit Option!"></form>';
?>

This returns me with an unidentified index error for 'Subject' whenever I hit the Submit Option button. I did a print_r($_POST) and realized that my selected options for the drop-down list "Subject" did not pass through. (i.e. The $_POST array that was printed did not show anything selected options from the drop-down list)

Upvotes: 3

Views: 1700

Answers (2)

Death-is-the-real-truth
Death-is-the-real-truth

Reputation: 72289

To submit your selected value to PHP you need to put <select> inside <form> code like below:-

<html>
    <form method="post">
    
    <select name="Subject">
    <option value="One">One</option>
    <option value="Two">Two</option>
    </select>

    <input type="submit" name="submit" value="Submit Option!"></form>
</html>
<?php
if (isset($_POST['Subject'])){
echo $_POST['Subject']; 
}
?>

Upvotes: 3

Chris Forrence
Chris Forrence

Reputation: 10084

One of the first things to know about HTML forms is that, when a form is submitted, the information contained within it gets submitted. To submit a value for Subject, that field needs to be contained within the <form> element.

<html>
    <?php
    if (isset($_POST['submit'])) {
        echo $_POST['Subject']; 
    }
    ?>
    <form method="post">
        <select name="Subject">
            <option value="One">One</option>
            <option value="Two">Two</option>
        </select>

        <input type="submit" name="submit" value="Submit Option!">
    </form>
</html>

Upvotes: 3

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