CODEWITHSUNDEEP
bashsed
user101
user101

Reputation: 175

Text substitution in file while expanding variables, using them as string literals, and adding a newline

I want to replace anything that looks like

if (Thing *thing1 = Stuff) {

with 

Thing *thing1 = Stuff;
if (thing1) {

Essentially take declarations out of if statements.

I have all the parts and I see that they're correct, I'm just having trouble with the replacement 

grep '  if (.* = .*) {' $file | while read -r line ; do

    inside="$( echo "$line" | cut -d "(" -f2 | cut -d ")" -f1 );"
    object="$( echo $( echo "$inside" | cut -d "*" -f2 | cut -d "=" -f1 ) | xargs )"
    newIF="    if ($object) {"
    replacement="$inside\n$newIF"

    line_regexp="$(echo "$line" | sed -e 's/[]\/$*.^|[]/\\&/g')"
    replacement_regexp="$(echo "$replacement" | sed -e 's/[\/&]/\\&/g')"

    sed -i.bak "s/$line_regexp/$replacement_regexp/g" $file


done

Edit thanks to: https://superuser.com/questions/422459/substitution-in-text-file-without-regular-expressions

Now I just have to figure out how to turn "\n" into an actual newline

Upvotes: 0

Views: 36

Answers (1)

SLePort
SLePort

Reputation: 15461

This sed should work for you:

$ sed -n 's/if (\([^ ]* \*\([^ ]*\) = [^)]*\)) {/\1;\nif (\2) {/p' <<< "if (Thing *thing1 = Stuff) {"
Thing *thing1 = Stuff;
if (thing1) {

Upvotes: 1

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