CODEWITHSUNDEEP
javascriptjquery
rachana
rachana

Reputation: 21

Merge multiple objects into single object with making array of same property values

I have five json objects obj1 ,obj2,obj3,obj4 and obj5, i want to merge them and crete a single json object and obj have same columns. The resultant json should have all the values from all objects
Question:

var obj1 = {
    "DOP":"manu",
    "Resolution":23,
    "sensor":"SE"
}

var obj2 = {
    "DOP":"mansa",
    "Resolution":22,
    "sensor":"PS"
}

like that all five object data and results should update only rows not as columns and expected result should be

var result = {
    "Dop":["manu","mansa"],
    "Resolution":[23,25],
    "Sensor":["SE","PS"]
}

Upvotes: 2

Views: 2521

Answers (4)

Haresh Vidja
Haresh Vidja

Reputation: 8496

You can merge object based on passing unlimited objects as arguments in myCustomMerge() function

function myCustomMerge() {
    var return_obj = {};
    for (i in arguments) {
        obj = arguments[i];
        for (j in obj) {
            if (return_obj[j] == undefined) {
                return_obj[j] = [obj[j]];
            } else {
                return_obj[j].push(obj[j]);
            }
        }
    }
    return return_obj;
}


var obj1 = {
    "DOP": "manu",
    "Resolution": 23,
    "sensor": "SE"
}

var obj2 = {
    "DOP": "mansa",
    "Resolution": 22,
    "sensor": "PS",
    "special_obj2": "My Special Value"
}

var obj3 = {
    "DOP": "top",
    "Resolution": 36,
    "sensor": "ME",
    "special_obj2": "My Special Value 2"
}

var merged_obj = myCustomMerge(obj1, obj2, obj3);
console.log(merged_obj);

Upvotes: 1

Yeshvant Kumar Bhavnasi
Yeshvant Kumar Bhavnasi

Reputation: 41

var x ={ "student-marks":{'math':1,'physics':5} }; var y ={ "student-marks":{'chemistry':3,'history':2} }; $.extend(true, {}, x, y);

I got the answer from here: How to merge two object values by keys

Upvotes: 0

ricky
ricky

Reputation: 1674

The way you want result is illegal. All you can have array of your json.

var result = [{ "DOP":"mansa", "Resolution":22, "sensor":"PS" },
              { "DOP":"manu", "Resolution":23, "sensor":"SE" }   
             ]

Upvotes: 0

Bartłomiej Gładys
Bartłomiej Gładys

Reputation: 4615

You can use for(x in obj)

var result = {}
for (x in obj1) { result[x] = obj1[x] + ', ' + obj2[x] }
//Object {DOP: "manu, mansa", Resolution: "23, 22", sensor: "SE, PS"}

Upvotes: 1

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