CODEWITHSUNDEEP
pythonpython-2.7
user5393628
user5393628

Reputation:

Convert string type array to array

I have this:

[s[8] = 5,

 s[4] = 3,

 s[19] = 2,

 s[17] = 8,

 s[16] = 8,

 s[2] = 8,

 s[9] = 7,

 s[1] = 2,

 s[3] = 9,

 s[15] = 7,

 s[11] = 0,

 s[10] = 9,

 s[12] = 3,

 s[18] = 1,

 s[0] = 4,

 s[14] = 5,

 s[7] = 4,

 s[6] = 2,

 s[5] = 7,

 s[13] = 9]

How can I turn this into a python array where I can do for items in x: ?

Upvotes: 0

Views: 123

Answers (4)

Bruno Abud Cardoso
Bruno Abud Cardoso

Reputation: 11

If you want the array to have the same name that is in the input string, you could use exec. This is not very pythonic, but it works for simple stuff

string = ("[s[8] = 5, s[4] = 3, s[19] = 2,"
   "s[17] = 8, s[16] = 8, s[2] = 8,"
   "s[9] = 7,  s[1] = 2,  s[3] = 9,"
   "s[15] = 7, s[11] = 0, s[10] = 9,"
   "s[12] = 3, s[18] = 1, s[0] = 4,"
   "s[14] = 5, s[7] = 4,  s[6] = 2,"
   "s[5] = 7, s[13] = 9]")

items = [item.rstrip().lstrip() for item in string[1:-1].split(",")]
name = items[0].partition("[")[0]
# Create the array
exec("{} = [None] * {}".format(name, len(items)))
# Populate with the values of the string
for item in items:
    exec(items[0].partition("[")[0] )

This will generate an array named "s" and if there is an index missing it will be initialized as None

Upvotes: 1

HEADLESS_0NE
HEADLESS_0NE

Reputation: 3536

An easy way, although less efficient than Kevin's solution (without using regular expressions), would be the following (where some_array is your string):

sub_list = some_array.split(',')
some_dict = {}

for item in sub_list:
    sanitized_item = item.strip().rstrip().lstrip().replace('=', ':')

    # split item in key val
    k = sanitized_item.split(':')[0].strip()
    v = sanitized_item.split(':')[1].strip()

    if k.startswith('['):
        k = k.replace('[', '')

    if v.endswith(']'):
        v = v.replace(']', '')

    some_dict.update({k: int(v)})

print(some_dict)
print(some_dict['s[9]'])

Output sample:

{'s[5]': 7, 's[16]': 8, 's[0]': 4, 's[9]': 7, 's[2]': 8, 's[3]': 9, 's[10]': 9, 's[15]': 7, 's[6]': 2, 's[7]': 4, 's[14]': 5, 's[19]': 2, 's[17]': 8, 's[4]': 3, 's[12]': 3, 's[11]': 0, 's[13]': 9, 's[18]': 1, 's[1]': 2, 's8]': 5}
7

Upvotes: 0

SilentLupin
SilentLupin

Reputation: 658

Assuming this is one giant string, if you want print s[0] to print 4, then you need to split this up by the commas, then iterate through each item.

inputArray = yourInput[1:-1].replace(' ','').split(',\n\n')
endArray = [0]*20
for item in inputArray:
    endArray[int(item[item.index('[')+1:item.index(']')])]= int(item[item.index('=')+1:])
print endArray

Upvotes: 0

Kevin
Kevin

Reputation: 76194

import re

data = """[s[8] = 5,

 s[4] = 3,

 s[19] = 2,

 s[17] = 8,

 s[16] = 8,

 s[2] = 8,

 s[9] = 7,

 s[1] = 2,

 s[3] = 9,

 s[15] = 7,

 s[11] = 0,

 s[10] = 9,

 s[12] = 3,

 s[18] = 1,

 s[0] = 4,

 s[14] = 5,

 s[7] = 4,

 s[6] = 2,

 s[5] = 7,

 s[13] = 9]"""

d = {int(m.group(1)): int(m.group(2)) for m in re.finditer(r"s\[(\d*)\] = (\d*)", data)}
seq = [d.get(x) for x in range(max(d))]
print(seq)
#result: [4, 2, 8, 9, 3, 7, 2, 4, 5, 7, 9, 0, 3, 9, 5, 7, 8, 8, 1]

Upvotes: 4

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