CODEWITHSUNDEEP
pythonnumpy
jvnna
jvnna

Reputation: 61

numpy.savetxt() -- tuple index out of range when writing string to text file

I am trying to write two strings into a .txt file using numpy.savetxt(). I want the strings to be on consecutive lines. However, when I run my code, I get the following error:

ncol = X.shape[1]

IndexError: tuple index out of range

Which occurs at the first line I call np.savetxt(). My code is below:

import numpy as np

data=np.loadtxt('data.txt')
name1 = 'James'
name2 = 'James 2'

hi = 'Hello {}'.format(name1)
bye  = 'Goodbye {}'.format(name2)

np.savetxt('greet.txt', hi, fmt="%s", newline='\n')
np.savetxt('greet.txt', bye, fmt="%s")

I've tried it without fmt, changing '%s' to other things, but they all give me the same error. Can anyone tell me what I'm doing wrong?

Upvotes: 0

Views: 1080

Answers (1)

Alber8295
Alber8295

Reputation: 763

According to the @moses-koledoye comment and @jvnna's answer, the following is the correct answer.

The hi and bye variables are of type string

hi = 'Hello {}'.format(name1)
bye  = 'Goodbye {}'.format(name2)

You are trying to save them to a txt file with the numpy function np.savetxt, according to the documentation:

Save an array to a text file.

So the hi and bye variables must be of type np.array in order to be handled with that function. Also, some reshape is needed.

A snippet code that does the trick could be:

hi = 'Hello {}'.format(name1)
bye  = 'Goodbye {}'.format(name2)

hi = np.array(hi).reshape(1, )  # This does the trick for hi
bye  = np.array(bye).reshape(1, ) # This does the trick for bye

np.savetxt('greet.txt', hi, fmt="%s", newline='\n')
np.savetxt('greet.txt', bye, fmt="%s")

Upvotes: 0

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