CODEWITHSUNDEEP
objective-cfirebasefirebase-dynamic-links
Kavitha Pai
Kavitha Pai

Reputation: 51

Firebase dynamic linking - Continueuseractivity not returning dynamic link url

My requirement is to handle universal links on the iOS application. But the dynamic link.url seems to be returning an error as below - 

"@"error" : @"unauthorized user: username=social-app-invite methodName=/FirebaseLookupService.LookupAppsSummary protocol=loas securityLevel=integritY"

When i click on a dynamic link (https://****.app.goo.gl/****) from the notes app, my ios app will be directed to the following callback -> In this function i have the following code -

- (BOOL)application:(UIApplication *)application continueUserActivity:(NSUserActivity *)userActivity restorationHandler:(void(^)(NSArray * __nullable restorableObjects))restorationHandler
{
NSURL *incomingURL = userActivity.webpageURL;
if(incomingURL){
    BOOL handled = [[FIRDynamicLinks dynamicLinks]
                    handleUniversalLink:incomingURL
                    completion:^(FIRDynamicLink * _Nullable dynamicLink,
                                 NSError * _Nullable error) {
                        if (dynamicLink.url){`
                           **HANDLE THE DYNAMIC LINK HERE**
                        }else{
                           **CODE IS RETURNING ERROR** NSLog(@"error %@",error);
                        }
                    }];
    return handled;
}else{
    return false;
}

}

I have followed the firebase documentation correctly. Please suggest what is going wrong here?

Upvotes: 2

Views: 3161

Answers (3)

cybergen
cybergen

Reputation: 3157

I also met this issue. handleUniversalLink() returned always false. In my case my link parameter contained not just a URL but also parameters. So the final dynamic link got two question marks in it.

https://app-id.app.goo.gl/?link=https://www.domain.com/resource?someParam=someValue&ibi=com.domain.appname

If I escape the inner URL (link parameter) with percent escapes, it works fine.

https://app-id.app.goo.gl/?link=https%3A%2F%2Fwww.domain.com%2Fresource%3FsomeParam%3DsomeValue&ibi=com.domain.appname

Upvotes: 3

Kavitha Pai
Kavitha Pai

Reputation: 51

I was able to get the dynamic link url value. There was an additional check in my code as below -

if (launchOptions != nil) {
[FIROptions defaultOptions].deepLinkURLScheme = URL_SCHEME;

}

Because of this check, the URL scheme was never getting initialised and hence was erroring out.

The code that i have posted above should return the right dynamic link url.

Thanks.

Upvotes: 0

Aklesh Rathaur
Aklesh Rathaur

Reputation: 1847

Try this one.

- (BOOL)application:(UIApplication *)application continueUserActivity:(NSUserActivity *)userActivity restorationHandler:(void(^)(NSArray * __nullable restorableObjects))restorationHandler
{
    NSURL *url = userActivity.webpageURL;


    FIRDynamicLinks *links = [FIRDynamicLinks dynamicLinks];
    if([links matchesShortLinkFormat:url])
    {
        [links resolveShortLink:url completion:^(NSURL * _Nullable url, NSError * _Nullable error)
        {
                NSString *message =
                [NSString stringWithFormat:@"Deep link  \n:%@",
                 url];

                [[[UIAlertView alloc] initWithTitle:@"Deep-link Data"
                                            message:message
                                           delegate:nil
                                  cancelButtonTitle:@"OK"
                                  otherButtonTitles:nil] show];



        }];

        return YES;
    }
 return false;
}

Upvotes: 0

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