Reputation: 4487
Table Name : sample
Column Name : id,name
Every Row Create Separate tag with inside.
Show the Xml value like this
<Details>
<id>1</id>
<name>na</name>
<Details>
<id>2</id>
<name>aa</name>
</Details>
</Details>
I tried like this but its not working
select
id 'Details\id'
,name 'Details\name'
from sample
How do get that xml output?
Upvotes: 1
Views: 368
Reputation: 15977
It is hardcoded but should work:
DECLARE @x xml
SELECT @x = (
SELECT x+''
FROM (
SELECT '%details?%id?'+CAST(id as nvarchar(max))+'%/id?%name?'+name+'%/name?' x
FROM [sample] s
UNION ALL
SELECT '%/details?'
FROM [sample] s
) as t
FOR XML PATH('')
)
SELECT CAST(REPLACE(REPLACE((CAST(@x as nvarchar(max))),'%','<'),'?','>') as xml)
In [sample]
table I got:
(1,'na'),
(2,'aa'),
(3,'sd')
Output:
<details>
<id>1</id>
<name>na</name>
<details>
<id>2</id>
<name>aa</name>
<details>
<id>3</id>
<name>sd</name>
</details>
</details>
</details>
EDIT
Also it could be done with recursive CTE:
DECLARE @x xml
;WITH rec AS (
SELECT CAST((
SELECT TOP 1 id,
[name]
FROM [sample]
ORDER BY id DESC
FOR XML PATH('details')
) as xml) as d,
1 as [Level]
UNION ALL
SELECT CAST((
SELECT id,
[name],
cast(r.d as xml)
FROM [sample]
WHERE s.id = id
FOR XML PATH('details')
) as xml) as d,
r.[Level]+1
FROM [sample] s
INNER JOIN rec r
ON s.id = CAST(r.d.query('/details/id/text()') as nvarchar(max))-1
)
SELECT TOP 1 WITH TIES d
FROM rec
ORDER BY [Level] desc
Same output.
Upvotes: 2
Reputation: 13959
You can use query like this:
SELECT
*,
(SELECT
*
FROM #details
WHERE id = 2
FOR xml PATH ('Details'), TYPE)
FROM #details
WHERE id = 1
FOR xml PATH ('Details')
For inner loop you can use CTE
Table creation scripts :
CREATE TABLE #details (
id int,
name varchar(10)
)
INSERT INTO #details (id, name)
VALUES (1, 'test'), (2, 'test2')
Upvotes: 0