CODEWITHSUNDEEP
matlab
typos
typos

Reputation: 6632

How does dist function work in MATLAB?

I have a MATLAB code which I try to convert to C, and it works all fine, but I'm stuck at dist function. It says that it calculates the Euclidean distance weight function. Calculating the normal Euclidean distance function is pretty easy, but I don't exactly get what the weight means here. In the code that I want to convert there is 1x1000, or to say in another words just a row array with complex values (meaning x + yi). Then it does something like this:

if ((dist(sest(i), -1)) < (dist(sest(i), 1)))

As I said sest is the 1x1000 matrix of complex values, so it takes each value in a for loop and puts it into the dist function with -1 or 1, and the output of dist function in my case is again a complex number. Any idea what's going on behind the scene? What -1 and 1 is doing there? How is the Euclidean weight function calculated here?

Upvotes: 0

Views: 310

Answers (1)

jfish003
jfish003

Reputation: 1332

Here the

((dist(sest(i), -1))

is just the equivalent of

abs(sest(i) + 1)

and

for real numbers. ((dist(sest(i), 1))

is the equivalent of

abs(1-sest(i))

for real numbers.

for complex numbers it seems to be that

((dist(sest(i), -1))

is the equivalent of

conj(abs(real(sest(i)) + 1)+ imag(sest(i))*j)

and 

((dist(sest(i), 1))

is the equivalent of

abs(1 -real(sest(i))) + imag(sest(i)*j)

Upvotes: 1

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