CODEWITHSUNDEEP
c++stringwhile-loopstringstreamdeque
Mohit Kumar
Mohit Kumar

Reputation: 510

Iteration in while loop runs and ends without taking inputs?

I want to split string and store it in result deque according to current input and do this again while (count-- > 0)

count = 3 in this case.

input string : abc def ghi

   while (count-- > 0){
    cout << " start of while loop" << endl;
    deque<string> result;
    string str2;
    cin >> str2;
    istringstream iss(str2);
    for(string s; iss >> s; ){
      result.push_back(s);
    } 
    cout << "result.size() " << result.size() << endl;
    }
   }

Problem : result size remains 1 and while loop runs 3 times automatically.

Todo : result size should be 3 in 1 iteration

Output : 

start of while loop
abc def ghi
result.size() 1
start of while loop
result.size() 1
start of while loop     
result.size() 1

I should have been able to take inputs 3 times, but while loop runs 3 time automatically without taking inputs and ends. Why is it happening ?

Upvotes: 1

Views: 42

Answers (1)

Vaughn Cato
Vaughn Cato

Reputation: 64308

Instead of this:

  while (count-- > 0){
    cout << " start of while loop" << endl;
    deque<string> result;  // result created inside loop

you want this

  deque<string> result; // result created outside loop
  while (count-- > 0){
    cout << " start of while loop" << endl;

otherwise, result is being recreated for each iteration of the loop.

Also, it sounds like you are expecting abc def ghi to be treated a single input, but cin >> str2 reads one word, not one line. To read a line, use getline instead:

getline(cin,str2);

Upvotes: 3

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