CODEWITHSUNDEEP
jsfprettyfaces
asdlfkjlkj
asdlfkjlkj

Reputation: 2348

jsf: get id from rest url or rewrite url

Currently I rewrite url as below

.addRule(Join.path("/users").to("/views/user/index.jsf"))

But now I need to rewrite url which includes numbers(user id). For example, if I have url as /users/1 or /users/200, etc. I need to match them to view /views/user/profile.jsf

Similarly, I also need to rewrite urls /users/1/edit or /users/200/edit to /views/user/edit.jsf

How can I achieve this?

Upvotes: 0

Views: 459

Answers (1)

asdlfkjlkj
asdlfkjlkj

Reputation: 2348

This is what is working for me now but not sure if this is the correct way of doing things.

First I rewrite the url as .addRule(Join.path("/users/{id}").to("/views/user/show.jsf"))

and I make the url as 

<h:column>
                <f:facet name="header">Show</f:facet>
                <h:outputLink value="/users/#{user.id}">Show</h:outputLink>
            </h:column>

This generate the url as /users/1 or /users/200 etc.

Now I can access the user id parameter from jsf page show.xhtml as <h:outputText value="#{param['id']}" />

I can also access the parameter from bean as 

public void show(){
    Map<String, String> params = FacesContext.getCurrentInstance().
            getExternalContext().getRequestParameterMap();
    String user_id = params.get("id");
}

Or I can also do something like this

in show.xhtml as

<ui:param name="user" value="#{userController.show(param['id'])}" />

Name: #{user.firstName}

and in userController as 

public User show(Integer id){
    user = userService.findById(id);
    return user;

}

Upvotes: 0

Related Questions