CODEWITHSUNDEEP
pythondatetime
Zanam
Zanam

Reputation: 4807

python add array of hours to datetime

import timedelta as td I have a date time and I want to add an array of hours to it.

i.e. 

Date[0]
datetime.datetime(2011, 1, 1, 0, 0)

Date[0] + td(hours=9)
datetime.datetime(2011, 1, 1, 9, 0)

hrs = [1,2,3,4]
Date[0] + td(hours=hrs)

But obviously it is not supported.

Date array above is a giant array of size 100X1 and I want to add hrs = [1,2,3,4] to each row of Date to get a datetime array of size 100x4. So, a for loop is not going to work in my case.

Upvotes: 1

Views: 1480

Answers (1)

alecxe
alecxe

Reputation: 474231

Use a nested list comprehension and .replace() method. Sample for a list with 2 datetimes:

In [1]: from datetime import datetime

In [2]: l = [datetime(2011, 1, 1, 0, 0), datetime(2012, 1, 1, 0, 0)]

In [3]: hours = [1, 2, 3, 4]

In [4]: [[item.replace(hour=hour) for hour in hours] for item in l]
Out[4]: 
[[datetime.datetime(2011, 1, 1, 1, 0),
  datetime.datetime(2011, 1, 1, 2, 0),
  datetime.datetime(2011, 1, 1, 3, 0),
  datetime.datetime(2011, 1, 1, 4, 0)],
 [datetime.datetime(2012, 1, 1, 1, 0),
  datetime.datetime(2012, 1, 1, 2, 0),
  datetime.datetime(2012, 1, 1, 3, 0),
  datetime.datetime(2012, 1, 1, 4, 0)]]

As a result a 2x4 list of lists.

Upvotes: 2

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