CODEWITHSUNDEEP
javareturnprintln
Michael Bishara
Michael Bishara

Reputation: 41

java println running function not returning function

FULL GITHUB FILES FOUND HERE

This is class Roulette.java

public static void main(String[] args) {
  System.out.println("Welcome to roulette " + Casino.player());
}

This is class Casino.java

public static String player() {
   Scanner sc = new Scanner(System.in);

   String name;
   System.out.println("Please enter your name : ");
   name = sc.nextLine();

   return name;
}

When running Roulette.java it's not printing Casino.player() as a variable of your name, but running the function and asking for your name. I want to run Casino.java first,ask your name, then run roulette and welcome you with your name. NOT ASK YOUR NAME AGAIN.

Note: New to programming

Upvotes: 0

Views: 42

Answers (2)

yitzih
yitzih

Reputation: 3118

The player() method in the Casino class prints out the message to input the users name. This will happen every time the method is called. To do what you want to do you need to create a conditional that checks if the player has already been set.

NOTE: This is not good practice or class design and in the future you should look into proper practice for class design and setting fields in a class. I would suggest posting this code on Code Review once you get it working to get a full answer on how this design can be improved.

Your Casino class should look something like this:

public class Casino {
    private static String player = "";

    public static String player() {
        if (player.equals("")) {
            Scanner sc = new Scanner(System.in);
            System.out.println("Please enter your name : ");
            this.player = sc.nextLine();;
        }
        return player;
    }
}

Upvotes: 2

secondbreakfast
secondbreakfast

Reputation: 4384

Try something like this

String player = Casino.player();

System.out.println("Welcome to roulette " + player);

Upvotes: 0

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