CODEWITHSUNDEEP
pythonnestedprivatepython-3.5
SungMin Jung
SungMin Jung

Reputation: 33

python - nested class access modifier

I'm trying to make an instance of a __Profile class in the constructor of the __Team class, but I can't get access to __Profile. How should I do it?

This is my code

class SlackApi:
    # my work
    class __Team:
        class __Profile:
            def get(self):
                # my work 
        def __init__(self, slackApi):
            self.slackApi = slackApi
            self.profile = __Profile()
            self.profile = __Team.__Profile()
            self.profile = SlackApi.__Team.__Profile()
            # I tried to all of these case, but I failed
            # I need to keep '__Team', '__Profile' class as private class

My python version is 3.5.1

Upvotes: 1

Views: 66

Answers (2)

user2357112
user2357112

Reputation: 281012

Python does not have access modifiers. If you try to treat __ like a traditional private access modifier, this is one of the problems you get. Leading double underscores cause name mangling - a name __bar inside a class Foo (or class __Foo, or any number of leading underscores before Foo) will be mangled to _Foo__bar.

If you really want to keep those leading double underscores, you'll have to explicitly mangle the names yourself:

self.profile = SlackApi._SlackApi__Team._Team__Profile()

This is also how you would access the __Profile class from outside of SlackApi altogether, so you're basically bypassing any pretense that these things are private.

Upvotes: 1

Bharel
Bharel

Reputation: 26900

You MAY access like so:

SlackApi._SlackApi__Team._Team__Profile

or like so:

self._Team__Profile

But that's just wrong. For your own convenience, don't make them a private class.

Upvotes: 0

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