CODEWITHSUNDEEP
javaregex
Roshan
Roshan

Reputation: 2059

java regex matches loop in reverse direction

I want to match regex pattern in java for particular text. In that while matching I need to find matches in reverse order.

Example:

Regex Pattern --  [([^]]*])

Input String  -- [blue][red][green]

Output   --  1st match --->[blue]
             2nd match --->[red]
             3rd match --->[green]

But I'm expecting match to be in reverse order.

Expected output  --    1st match --->[green]
             2nd match --->[red]
             3rd match --->[blue]

Please help how to form the regex to achieve the expected output.

Upvotes: 1

Views: 1286

Answers (2)

Konstantin Pribluda
Konstantin Pribluda

Reputation: 12367

Assuming you have complied regex date"

     ArrayList<String> strings = new ArrayList<>();
            Matcher foo = date.matcher("foo");
            while (foo.matches()) {
                strings.add(foo.group());
            }
            Collections.reverse(strings);

Upvotes: 1

vladsch
vladsch

Reputation: 606

Reverse regular expression in Java discusses the topic and I posted a solution there, added here for convenience.

If anyone is interested in a Java solution, I implemented a library to do just that. https://github.com/vsch/reverse-regex.

Handles all valid Java regex constructs and provides utility classes to wrap pattern, matcher and input for reverse searches to handle all need mappings and reversals.

Upvotes: 0

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