Reputation: 1999
Class clazz
has two methods methodA()
and methodB()
.
How to ensure that
methodB
is "blocked" if some threads are inmethodA
in Java (I am using Java 8)?
By "blocking methodB", I mean that "wait until no threads are in methodA()". (Thanks to @AndyTurner)
Note that the requirement above allows the following situations:
methodA
.methodB
while no threads are in methodA
.methodB
does not prevent other threads from entering methodA
. My trial: I use StampedLock lock = new StampedLock
.
methodA
, call long stamp = lock.readLock()
unlockB
and call lock.unlockRead(stamp)
in it.methodB
, call long stamp = lock.writeLock()
and lock.unlockWrite(stamp)
.However, this locking strategy disallows the second and the third situations above.
Edit: I realize that I have not clearly specified the requirements of the synchronization between methodA
and methodB
. The approach given by @JaroslawPawlak works for the current requirement (I accept it), but not for my original intention (maybe I should first clarify it and then post it in another thread).
Upvotes: 7
Views: 300
Reputation: 5588
I think this can do the trick:
private final Lock lock = new ReentrantLock();
private final Semaphore semaphore = new Semaphore(1);
private int threadsInA = 0;
public void methodA() {
lock.lock();
threadsInA++;
semaphore.tryAcquire();
lock.unlock();
// your code
lock.lock();
threadsInA--;
if (threadsInA == 0) {
semaphore.release();
}
lock.unlock();
}
public void methodB() throws InterruptedException {
semaphore.acquire();
semaphore.release();
// your code
}
Threads entering methodA
increase the count and try to acquire a permit from semaphore (i.e. they take 1 permit if available, but if not available they just continue without a permit). When the last thread leaves methodA
, the permit is returned. We cannot use AtomicInteger
since changing the count and acquiring/releasing permit from semaphore must be atomic.
Threads entering methodB
need to have a permit (and will wait for one if not available), but after they get it they return it immediately allowing others threads to enter methodB
.
EDIT:
Another simpler version:
private final int MAX_THREADS = 1_000;
private final Semaphore semaphore = new Semaphore(MAX_THREADS);
public void methodA() throws InterruptedException {
semaphore.acquire();
// your code
semaphore.release();
}
public void methodB() throws InterruptedException {
semaphore.acquire(MAX_THREADS);
semaphore.release(MAX_THREADS);
// your code
}
Every thread in methodA
holds a single permit which is released when the thread leaves methodA
.
Threads entering methodB
wait until all 1000 permits are available (i.e. no threads in methodA
), but don't hold them, which allows other threads to enter both methods while methodB
is still being executed.
Upvotes: 4
Reputation: 816
You would need an int to count threads in methodA, and ReentrantLock.Condition to signal all threads waiting in methodB once there are no threads in methodA:
AtomicInteger threadsInMethodA = new AtomicInteger(0);
Lock threadsForMethodBLock = new ReentrantLock();
Condition signalWaitingThreadsForMethodB = threadsForMethodBLock.newCondition();
public void methodA() {
threadsInMethodA.incrementAndGet();
//do stuff
if (threadsInMethodA.decrementAndGet() == 0) {
try {
threadsForMethodBLock.lock();
signalWaitingThreadsForMethodB.signalAll();
} finally {
threadsForMethodBLock.unlock();
}
}
}
public void methodB() {
try {
threadsForMethodBLock.lock();
while (!Thread.isInterrupted() && threadsInMethodA.get() != 0) {
try {
signalWaitingThreadsForMethodB.await();
} catch (InterruptedException e) {
Thread.interrupt();
throw new RuntimeException("Not sure if you should continue doing stuff in case of interruption");
}
}
signalWaitingThreadsForMethodB.signalAll();
} finally {
threadsForMethodBLock.unlock();
}
//do stuff
}
So each thread entering methodB will first check if nobody in methodA, and signal previous waiting threads. On the other hand, each thread entering methodA will increment counter to prevent new threads doing work in methodB, and on decrement it will release all the threads waiting to do stuff in methodB if no threads left inside methodA.
Upvotes: 0
Reputation: 12958
In very simple terms what you all need is ENTER methodB only if no thread inside methodA
.
methodA()
. You should have a lock/mutex
assigned to protect the variable count
.count++
.count--
.Threads that are entering methodB first should check whether count == 0
.
methodA(){
mutex.lock();
count++;
mutex.signal();
//do stuff
mutex.lock();
count--;
mutex.signal();
}
methodB(){
mutex.lock();
if(count != 0){
mutex.signal();
return;
}
mutex.signal();
//do stuff
}
Upvotes: 0
Reputation: 682
Why not using an kind of external orchestrator? I mean another class that will be responsible to call the methodA or methodB when it allowed. Multi-thread can still be handle via locking or maybe just with some AtomicBoolean(s).
Please find below a naive draft of how to do it.
public class MyOrchestrator {
@Autowired
private ClassWithMethods classWithMethods;
private AtomicBoolean aBoolean = = new AtomicBoolean(true);
public Object callTheDesiredMethodIfPossible(Method method, Object... params) {
if(aBoolean.compareAndSet(true, false)) {
return method.invoke(classWithMethods, params);
aBoolean.set(true);
}
if ("methodA".equals(method.getName())) {
return method.invoke(classWithMethods, params);
}
}
}
Upvotes: 0
Reputation: 2121
You can't really prevent that methodA or methodB is called (while other threads are inside the other method) but you can implement thread intercommunication in such a way so that you can still achieve what you want.
class MutualEx {
boolean lock = false;
public synchronized void methodA() {
if (lock) {
try {
wait();
}catch (InterruptedException e) {
}
}
//do some processing
lock = true;
notifyAll();
}
public synchronized void methodB() {
if (!lock) {
try {
wait();
}catch (InterruptedException e) {
}
}
//do some processing
lock = false;
notifyAll();
}
}
Now, for this to work any Thread object you create should have a reference to the same instance of MutualEx object.
Upvotes: 0