CODEWITHSUNDEEP
androidfirebasefirebase-realtime-database
Seenu69
Seenu69

Reputation: 1054

Firebase equalTo() not fetching desired results

I'm using Firebase. Where I need to fetch the record for a particular attribute. But when I have used the Firebase query method, I'm unable to get the actual result. Following is my code:

Firebase ref = ZopOrderingAplication.getFirebaseInstance();
Firebase retailerMastRef = ref.child("Retailer_Master");

Here s the query I'm using:

Query queryRef = retailerMastRef.orderByChild("user_name").equalTo("8105409301","user_name");

Here is the function I'm using to fetch the records:

queryRef.addListenerForSingleValueEvent(new ValueEventListener() {
            @Override
            public void onDataChange(DataSnapshot dataSnapshot) {
                long getChildCount = dataSnapshot.getChildrenCount();
                Log.i(TAG,"getChildCount: "+getChildCount);

                //Retailer_Master retailerObj = dataSnapshot.getValue(Retailer_Master.class);

                //Log.i(TAG,"retailer phone queryRef: "+retailerObj.getPhone());
            }

            @Override
            public void onCancelled(FirebaseError firebaseError) {

            }
        });

Here is the data in my firebase databse: enter image description here

Upvotes: 0

Views: 455

Answers (1)

Nishant Dubey
Nishant Dubey

Reputation: 2872

I think you need to try this:

Query queryRef = retailerMastRef.orderByChild("user_name").equalTo("8105409301");

Remove user_name from equalTo() as you have it in orderByChild.

Hope this helps. Do let me know if it changes anything for you.

Upvotes: 1

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