CODEWITHSUNDEEP
androidfirebasefirebase-realtime-database
jazzbpn
jazzbpn

Reputation: 7368

Is it possible to make different Firebase Database for Release and Debug mode in a single project/app?

Here we are working on the project that uses the Firebase Realtime Database. Is it possible to make different Firebase Database for Release and Debug mode in single Android app?

Project:(App with release/debug mode)

  1. Debug Mode(Test Environment) - Firebase Database 1
  2. Release Mode(Production Environment) - Firebase Database 2

What is the best idea to solve this Test/Production environment for Firebase Database?

Upvotes: 8

Views: 1883

Answers (3)

vepzfe
vepzfe

Reputation: 4537

You can create separate databases under the same project and use them for your debug and release builds.

In the code, just point get instances for different databases based on which build it is. 

FirebaseDatabase firebaseDatabase;
if (BuildConfig.DEBUG) {
    //Url of new database
    firebaseDatabase = FirebaseDatabase.getInstance("https://app-1234.firebaseio.com/");
} else {
    //For release builds use the default database
    firebaseDatabase = FirebaseDatabase.getInstance();
}

Upvotes: 0

John O'Reilly
John O'Reilly

Reputation: 10350

Rather than using google-services.json to drive initialisation of Firebase (assuming that's what you're currently doing?), I'd suggest dynamically creating FirebaseApp using something like following

    String apiKey;
    String databaseUrl;

    if (useDebugDatabase) {
        apiKey = "xxxxxx";
        databaseUrl = "<debug firebase database url>";
    } else {
        apiKey = "xxxxxx"
        databaseUrl = "<release firebase database url>";
    }


    FirebaseOptions firebaseOptions = new FirebaseOptions.Builder()
            .setApiKey(apiKey)
            .setApplicationId(context.getString(R.string.google_app_id))
            .setDatabaseUrl(databaseUrl)
            .build();
    FirebaseApp firebaseApp = FirebaseApp.initializeApp(context, firebaseOptions, "MyApp");

    FirebaseDatabase database = FirebaseDatabase.getInstance(firebaseApp);

Upvotes: 1

Frank van Puffelen
Frank van Puffelen

Reputation: 599716

There is only a single database in a project at the moment. So either you'll need to model debug and release data into the same database or you'll need a separate project for each.

Many of these scenarios are covered in this blog post: Organizing your Firebase-enabled Android app builds.

Upvotes: 3

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