Reputation: 1
I use golang
and mgo
, mongodb version is 3.2.9
For example i have two documents in one collection:
{"groupId" : 4, "name" : "email", "value" : "[email protected]"}
{"groupId" : 4,"name" : "phoneNumber","value" : "000000000"}
I know phoneNumber (value and name)
and I need to find email (value).
It can be simple done in two queries: first by phoneNumber I found groupId and then by groupId i found email.
Is it possible to do it in one query (using golang and mgo)?
Upvotes: 0
Views: 1364
Reputation: 103335
Yes, you would need to run an aggregation pipeline of the form:
var pipeline = [
{
"$group": {
"_id": "$groupId",
"entries": {
"$push": {
"name": "$name",
"value": "$value"
}
}
}
},
{
"$match": {
"entries.name" : "phoneNumber",
"entries.value" : "000000000"
}
},
{
"$project": {
"item": {
"$arrayElemAt": [
{
"$filter": {
"input": "$entries",
"as": "item",
"cond": { "$eq": [ "$$item.name", "email" ] }
}
}, 0
]
}
}
},
{
"$project": {
"_id": 0,
"email": "$item.value"
}
}
]);
db.collection.aggregate(pipeline);
Sample Output
{ "email" : "[email protected]" }
of which the equivalent mGo expression follows (untested):
pipeline := []bson.D{
bson.M{
"$group": bson.M{
"_id": "$groupId",
"entries": bson.M{
"$push": bson.M{
"name": "$name",
"value": "$value"
}
}
}
},
bson.M{
"$match": bson.M{
"entries.name" : "phoneNumber",
"entries.value" : "000000000"
}
},
bson.M{
"$project": bson.M{
"item": bson.M{
"$arrayElemAt": [
bson.M{
"$filter": bson.M{
"input": "$entries",
"as": "item",
"cond": bson.M{ "$eq":
[]interface{}{ "$$item.name", "email" }
}
}
}, 0
]
}
}
},
bson.M{
"$project": bson.M{
"_id": 0,
"email": "$item.value"
}
}
}
pipe := collection.Pipe(pipeline)
iter := pipe.Iter()
Upvotes: 0