Reputation: 656
I have this document's structure:
{
Id: "id_value",
Elements:[
{
InnerId: "inner_id_value1",
Value: "apple"
},
{
InnerId: "inner_id_value2",
Value: "pear"
},
{
InnerId: "inner_id_value3",
Value: "banana"
}
]
}
What i need to do is create a query which receives in input an array (for example ["apple","banana","coconut"]
) and returns to me:
{
Id: "id_value",
Elements:[
{
InnerId: "inner_id_value1",
Value: "apple"
},
{
InnerId: "inner_id_value3",
Value: "banana"
}
]
}
Is it possible do it in Mongo with a single query?
Upvotes: 4
Views: 589
Reputation: 61235
You simply need to $filter
the array and keep only those subdocument where the value is a subset of your input array. Note that value here is one element array where element is the embedded field value
.
let fruits = ["apple","banana","coconut"];
db.collection.aggregate([
{ "$project": {
"Element": {
"$filter": {
"input": "$Element",
"as": "el",
"cond": {
"$setIsSubset": [ [ "$$el.Value" ], fruits ]
}
}
}
}}
])
Starting from MongoDB 3.4* you can use the $in
operator in the $project
stage.
db.collection.aggregate([
{ "$project": {
"Element": {
"$filter": {
"input": "$Element",
"as": "el",
"cond": {
"$in": [ "$$el.Value", fruits ]
}
}
}
}}
])
*Unreleased version of MongoDB as the time of this writing
Upvotes: 4