Reputation: 3545
Basic question on .splice()
method, and how best to remove an element from an array.
I want to remove an item from an array with .splice()
but when I do, I want to have the original array minus the removed element returned. .splice()
returns the removed element instead.
var arr = [1, 2, 3, 4, 5, 6, 7]
var newArr = arr.splice(3, 1)
console.log(newArr) // [4]
// whereas I want [1, 2, 3, 5, 6, 7]
What's the best, and most eloquent way to do this?
Upvotes: 2
Views: 9791
Reputation: 816384
.splice
mutates the array in place and returns the removed elements. So unless you actually need a function that returns the array itself, just access arr
:
var arr = [1, 2, 3, 4, 5, 6, 7]
arr.splice(3, 1)
console.log(arr) // [1, 2, 3, 5, 6, 7]
You can create a wrapper function that performs the splice and returns the array:
function remove(arr, index) {
arr.splice(index, 1)
return arr;
}
var newArr = remove(arr, 3);
// Note: `newArr` is not a new array, it has the same value as `arr`
If you want to create a new array, without mutating the original array, you could use .filter
:
var newArr = arr.filter(function(element, index) {
return index !== 3;
}); // [1, 2, 3, 5, 6, 7]
arr; // [1, 2, 3, 4, 5, 6, 7]
Upvotes: 6
Reputation: 1170
Using the spread operator, you can do:
var arr = [1,2,3,4,5,6],
indexToRemove = 3,
newArr = [
...arr.slice(0,indexToRemove),
...arr.slice(indexToRemove+1)
]
Or if you want to use ES5, it can look something like:
var arr = [1,2,3,4,5,6],
indexToRemove = 3,
newArr = [].concat(arr.slice(0,indexToRemove)).concat(arr.slice(indexToRemove+1))
Upvotes: 6