Reputation: 19
I have a table contains order information like below:
As we can see from that table, each order_no has several duplicates. So what I want is to keep only one row for each order_no (no matter which one it is)
Is anyone knows how to do this? (FYI, I am using Oracle 10)
Upvotes: 1
Views: 635
Reputation: 26200
Here is a query to remove semi-duplicates with precise order by differing field:
delete from message_part
where ts >= since and ts < since + 1
and rowid not in (
select distinct first_value(rowid) over (partition by id order by differing_field)
from message_part where ts >= since and ts < since + 1
);
Credits go to @a_horse_with_no_name and Oracle equivalent of Postgres' DISTINCT ON?
Upvotes: 0
Reputation:
If you don't care which row you get for each order_no, perhaps the simplest solution (before Oracle 12) is:
select [whatever columns you want, probably not rn - see below]
from ( select order_table.*,
row_number() over (partition by order_no order by null) as rn
)
where rn = 1
;
Upvotes: 1
Reputation:
This should work, even in your ancient and outdated Oracle version:
delete from order_table
where rowid not in (select min(rowid)
from order_table
group by order_no);
Upvotes: 2