CODEWITHSUNDEEP
python
Nan Hua
Nan Hua

Reputation: 3694

UnicodeDecodeError: 'ascii' codec can't decode byte 0xe2 in position 46: ordinal not in range

I know there're many UnicodeDecodeError around, but I can't find anyone explaining my issue.. And this error randomly jumped from an environment that I can't reproduce..

What I want is to just to compare two strings byte to byte (I don't want any encoding and decoding).

Note that I'm using python2.7 and str1 is from open('..', 'r').read() on linux.

Hope for your advices..

  def diff_str(str1, str2):
      minlen = min(len(str1), len(str2))
      if str1 == str2:
        return "All %d bytes same" %minlen

      for diff_pos in xrange(minlen):
        if str1[diff_pos] != str2[diff_pos]:
          break

      k = 100

      to_ret = "(%d vs %d) chars\n" % (len(str1), len(str2))
      to_ret += "diff starts at %d:\n" % diff_pos
      # error jumps out at here..
      to_ret += str1[diff_pos:diff_pos+k] + "\n"
      to_ret += str2[diff_pos:diff_pos+k] + "\n"
    return to_ret

Upvotes: 0

Views: 125

Answers (1)

ch271828n
ch271828n

Reputation: 17623

Firstly, please paste your string(or file) you want to compare and make the errors.

Have a try:

for uchar in your_string.decode('utf-8'):
    # compare chars

Do you want a binary comparsion? Then give it a try:

oneBuf = bytes(yourfile.read(1024))

Then compare the byte bufs.

Upvotes: 1

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