CODEWITHSUNDEEP
c++
gllwrnce
gllwrnce

Reputation: 59

C++ code skips over if statement. Doesn't allow user to give input

new to C++ programming. Can anyone tell me what's wrong with my following code? The problem right now is that the if statement is ignoring any value you give it, and just goes to the section of code within the if statement.

There's also a problem with the code within the if statement itself. It doesn't take any input from the user. Any help would be really appreciated! Thanks.

#include <stdio.h>
#define SIZE 80
#include <iostream>
int main(void)
{
  FILE * pFile;
  int c; // variable to hold character input by user
  char sentence[SIZE]; // create char array
  int i = 0; // initialize counter i
  int number;
  std::cout << "Give a number. 1 for file. Anything else for standard.";
  std::cin >> number;
  std::cin.clear();

  if(number=1)
  {
   printf("Enter sentence to append: ");
   fgets(sentence,256,stdin);
    pFile=fopen("mylog.txt","a");
    fputs(sentence,pFile);
    fclose(pFile);
  }
 else
 {

   // prompt user to enter line of text
   puts("Enter a line of text:");

   // use getchar to read each character
   while ((i < SIZE-1) && (c = getchar()) != '\n') {
   sentence[i++] = c;}

   sentence[i]= '\0';

   // terminate string
   // use puts to display sentence

   puts("\nThe line entered was:");
   puts(sentence);
 }


 }

Upvotes: 0

Views: 56

Answers (1)

Gavin
Gavin

Reputation: 4515

The = is an assignment operator. You are just setting the value of number to 1. The == operator will compare the two values.

Upvotes: 2

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