CODEWITHSUNDEEP
javaparsing
Lacey17
Lacey17

Reputation: 1

how to fix parsing issue?

im using jdk se and i keep getting a parsing issue

"error: reached end of file while parsing"

i dont really understand why i keep getting this issue i have my class closed and brackets in places i think i would need brackets.

import java.util.Scanner;

public class days_in_a_month {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);

System.out.print("Please enter a month:");
String month = input.nextLine();
input.nextLine();

System.out.print("Please enter a year:");
String year = input.nextLine();
input.nextLine();

  boolean isLeapYear = (year % 4 == 0 && year % 100 != 0)||(year % 400 == 0); 

    switch (month){
    case "1":
    case "3":
    case "5":
    case "7":
    case "8":
    case "10":
    case "12":
        System.out.println(month + " " + year + " has 31 days"); break;

    case "4":
    case "6":
    case "9":
    case "11":
        System.out.println(month + " " + year + " has 30 days"); break;

    case "2":
        if(isLeapYear)
        {
            System.out.println(month + " " + year + " has 29 days"); break;
        }
            else
        {
            System.out.println(month + " " + year + " has 28 days");
            }
        }
  }

Upvotes: 0

Views: 962

Answers (4)

eGoLai
eGoLai

Reputation: 360

The Best of The Best solve is:

package com.dayinmonth

import java.time.LocalDate;
import java.util.Scanner;

public class days_in_a_month {

    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);

        System.out.print("Please enter a month:");
        int month = input.nextInt();
        input.nextLine();

        System.out.print("Please enter a year:");
        int year = input.nextInt();
        input.nextLine();

        LocalDate date = LocalDate.of(year, month, 1);

        System.out.println(String.format("%d %d has %d days", date.getMonthValue(), date.getYear(), date.lengthOfMonth()));

    }
}

Upvotes: 0

Lucke
Lucke

Reputation: 316

the best way to solve is using some like this:

int year = input.nextInt();

Upvotes: 2

eGoLai
eGoLai

Reputation: 360

just define year variable as int:

int year = Integer.valueOf(input.nextLine());

The problem is that you cannot use % operator for Strings

Here is the full example:

package com.yourpackage;


import java.util.Scanner;

public class days_in_a_month {
    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);

        System.out.print("Please enter a month:");
        String month = input.nextLine();
        input.nextLine();

        System.out.print("Please enter a year:");
        int year = Integer.valueOf(input.nextLine());
        input.nextLine();

        boolean isLeapYear = (year % 4 == 0 && year % 100 != 0) || (year % 400 == 0);

        switch (month) {
            case "1":
            case "3":
            case "5":
            case "7":
            case "8":
            case "10":
            case "12":
                System.out.println(month + " " + year + " has 31 days");
                break;

            case "4":
            case "6":
            case "9":
            case "11":
                System.out.println(month + " " + year + " has 30 days");
                break;

            case "2":
                if (isLeapYear) {
                    System.out.println(month + " " + year + " has 29 days");
                    break;
                } else {
                    System.out.println(month + " " + year + " has 28 days");
                }
        }
    }
}

Don't forget to name your file for as "days_in_a_month" and to define the appopriate package in the top of the file!

Upvotes: 0

Thusitha Thilina Dayaratne
Thusitha Thilina Dayaratne

Reputation: 5712

In your code you are trying to use % operator with String

boolean isLeapYear = ((year % 4 == 0 && year % 100 != 0) || (year % 400 == 0);

Operator % can't be used with String

Upvotes: 0

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