Reputation: 825
I have the following PHP 5.4 script which selects from MySQL 5.7, and it works fine.
<?php
$link = new mysqli("localhost","my_username","my_password", "my_schema");
if (mysqli_connect_errno())
{
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$sugg_query =
"SELECT
s.prim_key,
s.created_date,
s.created_by,
s.suggestion
FROM suggestion s;";
if ($sugg_result = mysqli_query($link, $sugg_query))
{
// determine number of rows result set */
$sugg_row_cnt = mysqli_num_rows($sugg_result);
printf("Result set has %d rows.\n", $sugg_row_cnt);
while($sugg_row = mysqli_fetch_array($sugg_result))
{
echo "<br />";
echo
$sugg_row['prim_key'] . " " .
$sugg_row['created_date'] . " " .
$sugg_row['created_by'] . " " .
$sugg_row['suggestion'] . " " ;
}
/* close result set */
mysqli_free_result($sugg_result);
}
//Close the connection
mysqli_close($link);
//close PHP
?>
I'd like to add column headers to the result. If I change the SELECT statement to the following, I get a result where only the row count line is produced.
$sugg_query =
"SELECT
s.prim_key as 'Key',
s.created_date as 'Date',
s.created_by as 'Source',
s.suggestion as 'Suggestion'
FROM suggestion s;";
How can I obtain data values and column headers from a SELECT in PHP?
Upvotes: 0
Views: 1465
Reputation: 717
For getting the headers you can iterate a row like:
foreach($sugg_row as $header => $value){
echo $header;
}
So maybe something like this should work in your code:
$rows = mysqli_fetch_array($sugg_result)
foreach($rows[0] as $header => $value){
echo $header;
}
You need also to keep in count that mysqli_fetch_array() will return NULL if there is no rows
Upvotes: 1