CODEWITHSUNDEEP
batch-filecmd
Artoo
Artoo

Reputation: 69

Batch file that identifies if a named window is open, and then closes it

I have been using the following script to check if a particular named window is open.

I got it from this thread:-

How do you test if a window (by title) is already open from the command prompt?

ideally I will expand the else part to close the window if it is found to be open. 

@For /f "Delims=:" %A in ('tasklist /v /fi "WINDOWTITLE eq test.bat - Notepad"') do @if %A==INFO (echo Prog not running) else SET "BREX=Awesome" &echo %BREX%

Unfortunately when I run this script it returns three instances of my else string?

screenshot

Is there any way to reduce this down to returning one instance?

Upvotes: 2

Views: 4379

Answers (2)

Squashman
Squashman

Reputation: 14290

If you really want to do this with one line from the cmd prompt you can do this.

 cmd /v:on /c "@For /f "Delims=:" %A in ('tasklist /v /nh /fi "WINDOWTITLE eq test.bat - Notepad"') do @if %A==INFO (echo Prog not running) else (SET "BREX=Awesome") &echo !BREX!"

Or use some conditional execution.

tasklist /v /nh /fi "WINDOWTITLE eq test.bat - Notepad" |findstr /B /C:"INFO: No tasks are running">nul && (echo Program not running) || (echo Awesome)

Upvotes: 1

FloatingKiwi
FloatingKiwi

Reputation: 4506

You could use findstr instead. You're getting multiple lines of output as you're looping over each line of output

tasklist /v /fi "WINDOWTITLE eq test.bat - Notepad" | findstr /C:"No tasks are running" 
if %errorlevel% NEQ 0 (
  echo awesome
) else (
  echo Prog not running
)

Upvotes: 2

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