CODEWITHSUNDEEP
javascriptjquery
John
John

Reputation: 3945

extract string from string with unknown length

var largePictureURL = response.d[i];
//for this example see largePictureURL
largePictureURL = "../uploads/191mapTool_thumb.png_tempLargeFileName=mapTool.png"

largePictureURL will always contain _tempLargeFileName + actual file name. Without knowing the actual file name how I can extract _tempLargeFileName + actual file name from largePictureURL?

I know how to do it with indexes but as I said I will be unsure of the name of the file. One thing for sure though I want to extract the remaining part of the string. Please advise

UPDATE @gurvinder372

//thumbNailUrlANDlargeImageUrl = "../uploads/191mapTool_thumb.png_tempLargeFileName=mapTool.png"

var largePictureURL = thumbNailUrlANDlargeImageUrl.split("_tempLargeFileName=")[1];
//largePictureURL = "mapTool.png"

var thumbnailURL = thumbNailUrlANDlargeImageUrl.split("_thumb." + "png")[0];
//thumbnailURL = "../uploads/191mapTool_thumb.png_tempLargeFileName=mapTool.png"

Upvotes: 2

Views: 575

Answers (2)

gurvinder372
gurvinder372

Reputation: 68393

largePictureURL will always contain '_tempLargeFileName' + actual file name.

This is a good enough hint to try this

var fileName = largePictureURL.split( "_tempLargeFileName" )[1]

and if = is also appended after "_tempLargeFileName" then modify the same to 

var fileName = largePictureURL.split( "_tempLargeFileName=" )[1]

For getting everything before use the 0th index

var before = largePictureURL.split( "_tempLargeFileName=" )[0]

Upvotes: 4

ScottM
ScottM

Reputation: 660

You could use substring of the index like this:

var fileName = largePictureURL.substring(largePictureURL.indexOf("_tempLargeFileName"));

That will get you everything to the end of the string, starting with "_tempLargeFileName"

Upvotes: 3

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