Reputation: 11
# include <iostream>
# include <string.h>
using namespace std;
int main()
{
int a=10;
int b=20;
char op[10];
const char p='+';
cout<<"enter the operation"<<endl;
cin>>op;
if(!strcmp(op,p)==0)
{
cout<<a+b;
}
return 0;
}
compilation result
12 17 C:\Users\DELL\Documents\cac.cpp [Error] invalid conversion from 'char' to 'const char*' [-fpermissive]
I am a beginner. Please tell me what mistake have I done.
Upvotes: 0
Views: 959
Reputation: 3911
there is no version of strcmp that takes a single character as a parameter but instead it takes two string and compares them.
if you want to compare a single char variable with a string you can compare it with the first element of string or with any other element:
#include <iostream>
#include <string>
int main()
{
char op[10] = "Hi";
const char p = '+';
// if( strcmp( op, p) ) // error cannot covert parameter 2 from char to const char*
// cout << "op and p are identic" << std::endl;
// else
// std::cout << "op and b are not identic" << std::endl;
if(op[0] == p)
std::cout << "op[0] and p are identic" << std::endl;
else
std::cout << "op[0] and p are not identic" << std::endl;
const char* const pStr = "Bye"; //constant pointer to constant character string: pStr cannot change neither the address nor the value in address
const char* const pStr2 = "bye"; // the same as above
// pStr++; //error
// pStr[0]++; // error
if( !strcmp( pStr, pStr2) )
std::cout << "pStr and pStr2 are identic" << std::endl;
else
std::cout << "pStr and pStr2 are Not identic" << std::endl;
return 0;
}
Upvotes: 0
Reputation: 2890
This isn't about the difference between char
and const char
, but between char []
and char
.
strcmp
expects two character arrays.
op
is an array of (10) characters. Good: that's what strcmp
expects.
p
is a single character. Not good: strcmp
needs a char array, and p
isn't any kind of array, but a single character.
You can change p
from a single char '+' to a char array "+", or compare only the 0th character of op
, as suggested in a comment above.
Upvotes: 2