CODEWITHSUNDEEP
javaarrays
Andrew Ramnikov
Andrew Ramnikov

Reputation: 793

Break multiple numbers in array into digits and count the repeating numbers

i am trying to solve some basic java question:

i have an array like int[] x = { 12, 24, 33 };. I need to break it into digits like {1, 2, 2, 4, 3 ,3} and then count the repeating numbers this way: 1:1, 2:2, 3:2, 4:1.

Until now i got this code but i can't save the digits into array. Can some one help me ?

public class targil_2_3 {
    public static void main(String[] args) {

        int[] x = { 12, 24, 33 };
        int[] ara = new int[x.length * 2];

        for (int i = 0; i < x.length; i++) {
            for (int j = 0; j < 2; j++) {  
                ara[j] = x[i] % 10;
                x[i] = x[i] / 10;
                System.out.println(ara[j]);
            }
        }            
    }       
}

Upvotes: 0

Views: 153

Answers (4)

Spotted
Spotted

Reputation: 4091

import java.util.Arrays;
import java.util.Map;
import static java.util.stream.Collectors.*;

public class Use {
    public static void main(String[] args) {
        int[] x = { 12, 24, 33 };
        Map<Integer, Long> result = Arrays.stream(x).boxed()
                                        .map(String::valueOf)
                                        .collect(joining())
                                        .chars().boxed()
                                        .collect(groupingBy(Character::getNumericValue, counting()));
        System.out.println(result); //prints {1=1, 2=2, 3=2, 4=1}
    }
}

Explanation

  1. First line convert an int[] to a Stream<Integer> (for each element)
  2. Convert Stream<Integer> to Stream<String>
  3. Reduce the Stream<String> to String
  4. Create a Stream<Integer> (for each digit)
  5. Count the occurences of each digit in a Map

Upvotes: 2

Mohsen_Fatemi
Mohsen_Fatemi

Reputation: 3391

we have only 10 decimal digits from 0 to 9 , [0..9]

so we make an array with length 10 , like count :

int count[] = new int[10];
for(int i = 0 ; i < x.length ; i++){
     if( x[i] == 0 ){
         count[0]++;
         continue;
     }
     while(x[i]!=0){
         int index = x[i] % 10;
         count[index]++;
         x[i] /= 10;
     }
}

then we will have the number of digits in count array , so we can print it :

for(int i = 0 ; i < 10 ; i++)
    System.out.println(i+" : "+count[i]);

if your data is so big it is better to use Map there are many ways to do this

Upvotes: 1

Mikhail Kuchma
Mikhail Kuchma

Reputation: 583

You dont need to store individual digits, you need to store just count for digits. Lets assume, that you're working with 10 based numbers, then code can looks like 

public static void main(String[] args) {
    int[] x = { 12, 24, 33, 0, 10, 555 };

    int[] count = new int[10];
    for (int i = 0; i < x.length; i++) {
        int num  = x[i];
        if (num == 0) {
            count[0]++;
            continue;
        }

        while (num > 0) {
            count[num % 10]++;
            num = num / 10;
        }
    }

    System.out.println(Arrays.toString(count));
}

Output is

[2, 2, 2, 2, 1, 3, 0, 0, 0, 0]

Upvotes: 3

MordechayS
MordechayS

Reputation: 1546

Digits are 0-9. Build a counter array of size 10, and count each digit extracted in the proper index of the counter array ("counter[digit]++").

Edit: Of- course, in the end you can build the desired result array based on the counter array.

For example: result[0] = "0:" + counter[0];"

Good Luck!

Upvotes: 0

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